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Vladimir79 [104]
3 years ago
6

Create the Lewis structure of COCl2 using the following five steps. NOTE: Work only on the currently bolded step below - don't w

ork ahead to solve the final structure. Scroll down to see steps 3-5.
Step 1. Count valence electrons in the molecule or ion. Do this by adding the periodic group numbers for each atom in the structure and adjusting for charge. Enter and check your answer.
Step 2. Connect each pair of bonded atoms with a single bond by dragging bonds onto the molecule. Each bond decreases the number of available electrons by 2. Check your answer.
Step 3. Drag lone pairs of electrons to each terminal atom until each has an octet of electrons, or until all electrons are used. You may remove a lone pair by clicking on it. Check your answer.
Step 4. Place remaining electrons on the central atom. If the structure is already correct, or no electrons remain, check your answer.
Step 5. Examine the structure. If the central atom has less than eight valence electrons, create multiple bonds by changing a terminal atom lone pair to a second or third bond pair. Only C, N, O, P, and S commonly make multiple bonds. If the structure is already correct, check your answer.
Chemistry
1 answer:
slamgirl [31]3 years ago
6 0
M vl hm by tu lord tu checkbook x he
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How would you prepare 250 mL of a 0.100 M solution of fluoride ions<br> from solid CaF2?
andrey2020 [161]

In 250 mL of volumetric flask add 0.975875 grams of CaF_2 and dissolve it in the 250 mL of water.

Given:

The solid of calcium fluoride.

To prepare:

The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.

Method:

Molarity of the fluoride ion solution needed = M = 0.100 M

The volume of the fluoride ion solution needed = V = 250 mL

1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L

The moles of fluoride ion needed = n

According to the definition of molarity:

M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol

Moles of fluoride ion = 0.025 mol

We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2

Moles of calcium fluoride = 0.0125 mol

Mass of calcium fluoride needed to prepare the solution :

=0.0125 mol\times 78.07 g/mol=0.975875 g

Preparation:

  • Weight 0.975875 grams of calcium fluoride
  • Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
  • Now add a small amount of water to dissolve the calcium fluoride completely.
  • After this add more water up to the mark of the volumetric flask of volume 250 mL.

Learn more about molarity of solution ere:

brainly.com/question/10053901?referrer=searchResults

brainly.com/question/10270173?referrer=searchResults

3 0
3 years ago
Find the number of moles of water that can be formed if you have 154 mol of hydrogen gas and 72 mol of oxygen gas.
9966 [12]

Answer:

77

Explanation:

H2O needs 2 hydrogens and you have 154 so 154/2 is 77

thats the most you can do

7 0
3 years ago
What do all organic substances have in common
motikmotik
All organic substances contain carbon atoms.
6 0
2 years ago
Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully rea
gulaghasi [49]

Answer:

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na(s)  + Cl₂(g)  →  2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol . 23 g/mol = 105.8 g

3 0
3 years ago
Were are electrons located
lukranit [14]
Electrons are found in the cloud that's surrounded the nucleus of an atom 
8 0
2 years ago
Read 2 more answers
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