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Vladimir79 [104]
4 years ago
6

Create the Lewis structure of COCl2 using the following five steps. NOTE: Work only on the currently bolded step below - don't w

ork ahead to solve the final structure. Scroll down to see steps 3-5.
Step 1. Count valence electrons in the molecule or ion. Do this by adding the periodic group numbers for each atom in the structure and adjusting for charge. Enter and check your answer.
Step 2. Connect each pair of bonded atoms with a single bond by dragging bonds onto the molecule. Each bond decreases the number of available electrons by 2. Check your answer.
Step 3. Drag lone pairs of electrons to each terminal atom until each has an octet of electrons, or until all electrons are used. You may remove a lone pair by clicking on it. Check your answer.
Step 4. Place remaining electrons on the central atom. If the structure is already correct, or no electrons remain, check your answer.
Step 5. Examine the structure. If the central atom has less than eight valence electrons, create multiple bonds by changing a terminal atom lone pair to a second or third bond pair. Only C, N, O, P, and S commonly make multiple bonds. If the structure is already correct, check your answer.
Chemistry
1 answer:
slamgirl [31]4 years ago
6 0
M vl hm by tu lord tu checkbook x he
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at a given tempature gas with a pressure of 150 kpa has volume of 0.8 l if the pressure decreases to 75kpa and the temperature r
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  <span>P*V/T=constant 
so P*V= constant*T 
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What happens to the ionizing rate if the steps of ionizing polyprotic acid increases?
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<h3>An acid that contains more than one ionizable proton is a polyprotic acid. The protons of these acids ionize in steps. The differences in the acid ionization constants for the successive ionizations of the protons in a polyprotic acid usually vary by roughly five orders of magnitude.</h3>
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An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm
frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

 xA= 0.34, yA= 0.55

ii)      0.50 = 0.55 nv + 0.34 nL

     Therefore, nV =    0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii)  ρA= 0.791 g/cm3 and,  ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

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