Question

A 80-kg person running at 5 m/s is pushed by the wind for 20 seconds so that their velocity increases to 6 m/s. How much force does the wind apply to the runner

Answer 1

Answer:

The force applied by the wind to the runner is 4 N.

Explanation:

Given that,

Mass of the person, m = 50 kg

Initial speed, u = 5 m/s

Final speed, v = 6 m/s

Time, t = 20 s

We need to find the force applied by the wind to the runner. It is based on Newton's second law of motion. The force is given by :

$F=m\times a\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{80\times (6-5)}{20}\\\\F=4\ N$

So, the force applied by the wind to the runner is 4 N.