All categories

3 years ago

If John ran a 5-kilometer marathon, how long was that in meters? A. 50 m. B. 5,000 m. C. 500 m. D. 1000 m.

Physics

2 answers:

Vladimir79 [104]3 years ago

8 0

The answer is B good lessons

andreyandreev [35.5K]3 years ago

4 0

1 km = 1000 M . . 5 km = 5000 M The fact that John ran it is not involved anywhere in the math.

You might be interested in

PLEASE ASAP HELP, ILL GIVE WHATEVER POINTS I CAN BUT PLEASE HELP ASAP ASAP

dalvyx [7]

(1) The ball is in the air for 1.4 seconds.

(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.

(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.

(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.

(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s.

<h3>What is the time of motion of the ball?</h3>

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

h is the height of the cliff
g is acceleration due to gravity

t = √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

d is the horizontal distance travelled by the ball = 8.85 m

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

Learn more about horizontal velocity here: brainly.com/question/24949996

#SPJ1

5 0

1 year ago

Define relative velocity with an example. A man is going

makkiz [27]

Answer:

4.24m/s,45 degrees in forward direction

Explanation:

6 0

3 years ago

What’s 3 times 10 to the 8th power divided by 2.45 times 10 to the 9th power

Virty [35]

0.12244898 is the value obtained when solving the given.

Explanation:

Given:

3 times 10 to the 8th power can be expressed in equation format as $3 \times 10^{8}$ (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)

2.45 times 10 to the 9th power can be expressed in equation format as $2.45 \times 10^{9}$ (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)

Asked to find the solution when dividing the above,

$\frac{3 \times 10^{8}}{2.45 \times 10^{9}}=\frac{3}{2.45} \times 10^{8-9}$

When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘ $10^{9}$ ' goes to numerator changed as ' $10^{-9}$ ').

Now by solving the above equation, we get

$\frac{3}{2.45} \times 10^{8-9}=1.22 \times 10^{-1}=\frac{1.22}{10}=0.12244898$

5 0

3 years ago

A computer software update involved updating the flash memory of a hardware component. The update failed. A phone technician sai

Alexandra [31]

Answer:

Yes, it's true. Computers do work that way. It's experienced by one of the authors of the book how computers work.

Explanation:

3 0

3 years ago

Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vert

chubhunter [2.5K]

Answer:

362.41 km/h

Explanation:

F = Force

m = Mass = 84 kg

g = Acceleration due to gravity = 9.81 m/s²

C = Drag coefficient = 0.8

ρ = Density of air = 1.21 kg/m³

A = Surface area = 0.04 m²

v = Terminal velocity

F = ma

$F=\frac{1}{2}\rho CAv^2\\\Rightarrow mg=\frac{1}{2}\rho CAv^2\\\Rightarrow v=\sqrt{2\frac{mg}{\rho CA}}\\\Rightarrow v=\sqrt{2\frac{20\times 9.81}{1.21\times 0.8\times 0.04}}\\\Rightarrow v=100.66924\ m/s$

Converting to km/h

$100.66924\times 3.6=362.41\ km/h$

The terminal velocity of the stone is 362.41 km/h

5 0

3 years ago

Read 2 more answers