The balance chemical reaction is:
<span>6 Li(s) + N2(g) → 2 Li3N(s)
We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:
1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li</span>