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Elenna [48]
4 years ago
8

Average Amplitude of Waves

Physics
2 answers:
VLD [36.1K]4 years ago
7 0

Answer: The answer is 200 meters

Explanation:

vovikov84 [41]4 years ago
4 0

Answer:

200 (D)

Explanation:

You might be interested in
Which of the following quantities can be measured in the same units as Work?
arlik [135]

Answer:

Kinetic energy and potential energy.

Explanation:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v^2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared. Kinetic energy is usually measured in units of Joules (J); one Joule is equal to 1 kg m^2 / s^2.

The formula for potential energy depends on the force acting on the two objects. For the gravitational force, the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m/s^2 at the surface of the earth) and h is the height in meters. Notice that gravitational potential energy has the same units as kinetic energy, kg m^2/s^2. In fact, all energy has the same units, kg m^2/s^2, and is measured using the unit Joule (J).

Work is also measured with the unit Joule (J).

3 0
3 years ago
A 75 A resistor in a circuit has a current flowing through it of 2.0 A. What is
Reptile [31]

Answer:

The power dissipated by the resistor can be calculated as P = I^{2} R .

Explanation:

  • Joules heating law states that any conductor passed with the electric current produces heating effect which is the electric power loss.
  • The given circuit has, R = 75 ohm resistor (the unit is wrong i question because resistor's unit is ohm not Ampere).
  • Current flowing through the circuit is I = 2.0 A.
  • By using joules heating theory, P = I^{2} R,

                  or,   P = 2^{2} * 75

                  or,   P= 4*75

                 or,  P= 300 W.

  • So the power dissipated by the resistor in the circuit is 300 W.
7 0
3 years ago
Determine the resistance of a 250-w lightbulb connected to its proper source voltage of 110 v.
ollegr [7]
1.P=UI
2.U=IR
so P=U^2/R
R=U^2/P=110*110/250=48.4ohm
5 0
3 years ago
A dart is thrown horizontally at a target's center that is 5.00 m, away. The dart hits the target 0.150 m below the targets cent
boyakko [2]

Answer:

  v₀ₓ = 28.6 m / s

Explanation:

This is a missile throwing exercise

          y = v_{oy} t - ½ g t²

as the dart is thrown horizontally the vertical velocity is zero (I go = 0)

          y = - ½ g t²

          t = \sqrt{- \frac{2y}{g}  }

let's calculate

         t = \sqrt{- \frac{2 \  (-0.150)}{9.8} }

         t = 0.175 s

the expression for horizontal displacement is

         x = v₀ₓ t

         v₀ₓ = x / t

         v₀ₓ = 5.00 / 0.175

         v₀ₓ = 28.6 m / s

7 0
3 years ago
HELP PLZ HELP !!!!!!!!!!!
AURORKA [14]
Neon (10)
Sodium (11)
Silicon (14)
Iron (26)
Uranium (92)

7 0
3 years ago
Read 2 more answers
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