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jok3333 [9.3K]
3 years ago
11

If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 52.0 m/s in the opposite directi

on, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. Express your answer with the appropriate units.

Physics
1 answer:
stich3 [128]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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Tyler is in downtown San Antonio entertaining the tourists with amazing feats of physics. He carries a nickel
professor190 [17]

Answer:

The velocity of the nickel just before it hits the ground is approximately 49.3 m/s

Explanation:

In order to calculate the velocity of the nickel just before it hits the ground, we recall the kinematic equation of motion, v² = u² + 2·g·h, where the variables of the equation are defined as follows;

v = The velocity of the nickel just before it hits the ground after it is pushed off the observation deck

u = The initial velocity of the nickel just before it is pushed off the observation deck = 0 m/s

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which he nickel is pushed off the edge = 124 m

Substituting the given values and the constant, "g", we have;

v² = 0² + 2 × 9.8 × 124 = 2,430.4

v = √2,430.4

Using a graphing calculator, we have;

v = √2,430.4 = 14·√(62/5) ≈ 49.3

The velocity of the nickel just before it hits the ground = v ≈ 49.3 m/s.

3 0
3 years ago
A package rests on the floor of an elevator that is rising with constant speed. the elevator exerts an upward normal force on th
Tomtit [17]
Because the actual package isn't moving so the gravitational potential energy stays the same. kinetic energy is gained through motion of the object not the motion of the surroundings of the object so
unless the package is falling out of a window its losing gravitational potential energy and gaining kinetic energy. hope this helps :-) 
6 0
2 years ago
A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising spee
zmey [24]

Answer:

The average power delivered by the elevator motor during this period is 6.686 kW.

Explanation:

Given;

mass of the elevator, m = 636 kg

initial speed of the elevator, u = 0

time of motion, t = 4.5 s

final speed of the elevator, v = 2.05 m/s

The upward force of the elevator is calculated as;

F = m(a + g)

where;

m is mass of the elevator

a is the constant acceleration of the elevator

g is acceleration due to gravity = 9.8 m/s²

a = \frac{v-u}{t} \\\\a = \frac{2.05 -0}{4.5} \\\\a = 0.456 \ m/s^2

F = (636)(0.456 + 9.8)

F = (636)(10.256)

F = 6522.816 N

The average power delivered by the elevator is calculated as;

P_{avg} = \frac{1}{2} (Fv)\\\\P_{avg} = \frac{1}{2} (6522.816 \ \times \ 2.05)\\\\P_{avg} = 6685.89 \ W\\\\P_{avg} =  6.68589 \ kW\\\\P_{avg} =  6.686 \ k W

Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.

3 0
2 years ago
Which property remains unaffected during the rock cycle?
aivan3 [116]

the answer is B.) Mass of material.

6 0
3 years ago
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If an experiment involves a large volume of liquid a _______ would most likely be used to hold it.
Grace [21]
The answer is d a beacker
3 0
2 years ago
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