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Bad White [126]
3 years ago
10

A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches

the required takeoff velocity at the end of the runway. What is the time tTO needed to take off? Express your answer in seconds using three significant figures.
Physics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

{v}^{2}  =  {z}^{2}  + 2ax

v = z + at

First let's find the final velocity the plane will have at the end of the runway using the first equation:

{v}^{2}  =  {0}^{2}  + 2(5)(1800)

v = 60 \sqrt{5}

Now we can plug this into the second equation to find t:

60 \sqrt{5}  = 0 + 5t

t = 12 \sqrt{5}

Then using 3 significant figures we round to 26.8 seconds

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A 5.75 × 107 kg battle ship originally at rest fires a 1100-kg artillery shell horizontally with a velocity of 550 m/s. show ans
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Answer:

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Explanation:

M = mass of ship = 5.75\times 10^7\ kg

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As linear momentum is conserved

(M - m)u=-mv\\\Rightarrow u=-\frac{mv}{M - m}\\\Rightarrow u=-\frac{1100\times 550}{5.75\times 10^7+1100}\\\Rightarrow u=-0.01052\ m/s

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