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3 years ago

The weight of an objects can be calculated by multiplying mass by

Physics

2 answers:

Lana71 [14]3 years ago

7 0

Acceleration due to gravity.

dmitriy555 [2]3 years ago

6 0

It can be calculated by multiplying mass and free-fall acceleration

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The first law of thermodynamics states that △E = Q-w. is this also a statement of the principle of conversation of energy? A. Th

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Its A. The heat that flows into the system is transformed into work and a change in internal energy

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3 years ago

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In an experiment of a simple pendulum, measurements show that the pendulum has length し 0.397 ± 0.006 m, mass M-0.3172 ± 0.0002

vichka [17]

Answer:

1.)1.265+or minus 0.0006m

2).0.71%

Explanation:

See attached file

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3 years ago

True or False? Gases such as water vapor condense when they are *heated*.

scoundrel [369]

That statement is false.

"Condense" is what a gas does when it turns into liquid, and that's something that happens when the gas is cooled, not heated.

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4 years ago

PLEASE HELP!! Newtons first law states that if an objects velocity is changing a __________ must be acting on it. Question 1 opt

Anika [276]

Newtons first law states that if an objects velocity is changing a force must be acting on it.

Explanation:

Newton's first law of motion states that:

"An object at rest (or in uniform motion) will remain at rest (or will continue moving with the same velocity) unless acted upon an unbalanced force"

We can apply this law to a daily life example:

Take a book at rest on a table: the forces acting on the book are balanced. If we do not apply any other force, we know that the book will remain at rest: this is exactly what is summarized in Newton's first law.
Take a space probe moving in the interstellar space, very far from any planet or source of gravitational force. Since there are no forces acting on the proble, the probe will continue moving at the same velocity (same speed and same direction) forever, unless stopped by a new force acting on it.

This means that in order to put an object at rest in motion, or to stop an object already in motion, or to change its velocity, an unbalanced force needs to be applied: otherwise, the object will continue having the same velocity (which can be either zero or non-zero), so it will continue having same speed and same direction.

Learn more about Newton laws of motion:

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3 years ago

When the magnetic flux through a single loop of wire increases by , an average current of 40 A is induced in the wire. Assuming

Zielflug [23.3K]

COMPLETE QUESTION:

When the magnetic flux through a single loop of wire increases by 30 Tm^2 , an average current of 40 A is induced in the wire. Assuming that the wire has a resistance of 2.5 ohms , (a) over what period of time did the flux increase? (b) If the current had been only 20 A, how long would the flux increase have taken?

Answer:

(a). The time period is 0.3s.

(b). The time period is 0.6s.

Explanation:

Faraday's law says that for one loop of wire the emf $\varepsilon$ is

$(1). \: \: \varepsilon = \dfrac{\Delta \Phi_B}{\Delta t }$

and since from Ohm's law

$\varepsilon = IR$ ,

then equation (1) becomes

$(2). \: \:IR= \dfrac{\Delta \Phi_B}{\Delta t }.$

(a).

We are told that the change in magnetic flux is $\Phi_B = 30Tm^2$ , the current induced is $I = 40A$ , and the resistance of the wire is $R = 2.5\Omega$ ; therefore, equation (2) gives

$(40A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },$

which we solve for $\Delta t$ to get:

$\Delta t = \dfrac{30Tm^2}{(40A)(2.5\Omega)},$

$\boxed{\Delta t = 0.3s}$ ,

which is the period of time over which the magnetic flux increased.

(b).

Now, if the current had been $I =20A$ , then equation (2) would give

$(20A)(2.5\Omega)= \dfrac{30Tm^2}{\Delta t },$

$\Delta t = \dfrac{30Tm^2}{(20A)(2.5\Omega)},$

$\boxed{\Delta t = 0.6 s\\}$

which is a longer time interval than what we got in part a, which is understandable because in part a the rate of change of flux $\dfrac{\Delta \Phi_B}{\Delta t}$ is greater than in part b, and therefore , the current in (a) is greater than in (b).

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3 years ago