All categories

3 years ago

Please help on this one?

Physics

1 answer:

pashok25 [27]3 years ago

7 0

Answer:

B) It is connected in parallel and measures potential differences.

Explanation:

A voltmeter measures electrical potential differences between two points in an electric circuit. It is also connected in parallel to measure a device's voltage, while an ammeter is connected in series to measure a device's current.

Hope this helps! :)

You might be interested in

What is the final electron acceptor in noncyclic electron flow?

Phoenix [80]

Answer:

final electron acceptor in noncyclic electron flow is NADP+

Explanation:

solution

in the plant final electron acceptor in noncyclic electron flow is NADP+

because we know here that NADP+ is oxidized by nicotinamide adenine di nucleotide phosphates

and coenzyme that is act as electron transported agent

so as a oxidized substance that act as electron acceptor

so that as non cyclic electron flow final electron acceptor is NADP +

5 0

3 years ago

Two large, parallel, conducting plates are 1.00 cm apart and having electric charges of equal magnitudes (80.0 nC/m^2) and oppos

boyakko [2]

(a) 9040 V/m

The magnitude of the electric field between two parallel, oppositely charged plates is given by

$E=\frac{\sigma}{\epsilon_0}$

where

$\sigma$ is the charge surface density on each plate

$\epsilon_0 = 8.85\cdot 10^{-12}$ is the vacuum permittivity

In this problem, the magnitude of the charge density on each plate is

$\sigma = 80.0 nC/m^2 = 80.0\cdot 10^{-9} C/m^2$

Substituting into the formula, we find the magnitude of the electric field:

$E=\frac{80.0\cdot 10^{-9}}{8.85\cdot 10^{-12}}=9040 V/m$

(b) 90.4 V

The electric potential difference between the two plates is given by

$\Delta V=Ed$

where

E is the magnitude of the electric field

d is the separation between the two plates

In this problem, we have

E = 9040 V/m

d = 1.00 cm = 0.01 m

Substituting into the formula, we find

$\Delta V=(9040)(0.01)=90.4 V$

6 0

3 years ago

A 2N and an 6N force pull on an object to the right and a 4N force pulls on the object to the left. If the object has a mass of

wolverine [178]

Answer:

$16m/s^{2}$

Explanation:

Please ask if you have more questions!

3 0

3 years ago

What is the difference between a permanent magnet and a temporary magnet

lara31 [8.8K]

Pernament magnet is one that retains its magnetic properties for a long period of time. Temporary megnet only maintains its magnetism while in a magnetic field produced by permanent magnet or electric current.

4 0

3 years ago

Read 2 more answers

A speed-time graph is shown below:

alexandr1967 [171]

Answer:

<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)

Explanation:

<u>Average Acceleration</u>

The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

$\displaystyle \bar a=\frac{v_f-v_o}{t}$

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

$\displaystyle \bar a=\frac{4-0}{8}=0.5$

The average acceleration is 0.5 cm/s^2

A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

C) Incorrect. The average acceleration is 0.5 cm/s^2

D) Incorrect. The average acceleration is 0.5 cm/s^2

3 0

3 years ago