Answer:
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
Explanation:
Given:
Radius of sphere (r) = 12 cm = 0.12 m
Distance from the electric field R = 24 cm = 0.24 m
Magnitude (E) = 640 N/C
Find:
Charge density on the sphere
Computation:
Charge on the sphere (q) = (1/K)ER² (K = 9 × 10⁹)
Charge on the sphere (q) = [1/(9 × 10⁹)](640)(0.24)²
Charge on the sphere (q) = 4 × 10⁻⁹ C
Charge density on the sphere = q / [4πr²]
Charge density on the sphere = [4 × 10⁻⁹] / [4(3.14)(0.12)²]
Charge density on the sphere = [4 × 10⁻⁹] / [0.18]
Charge density on the sphere = 2.2 × 10⁻⁸ C/m²
Answer:
t = 186.2 μs
Explanation:
Current in LR series circuit
----(1)
steady current = I_{s} = V/R
time constant = τ =
= 0.268 ms
magnetic energy stored in coil = 
rate at which magnetic energy stored in coil= 
----(2)
rate at which power is dissipated in R:
---(3)
To find the time when the rate at which energy is dissipated in the coil equals the rate at which magnetic energy is stored in the coil equate (2) and (3)
[/tex]I=\frac{L}{R}\frac{dI}{dt}[/tex]----(4)
differentiating (1) w.r.to t
---(5)
substituting (5) in (4)
----(6)
equating (1) and (6)
L= 4.3 mH
R= 16 Ω
t = 186.2 μs
The acceleration of a 2000 kg truck that has an engine exerts 400 N of force <u>at 0.2 m/s².</u>
<u />
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass = 2000 kg
Force = 400 N
acceleration = F/mass
= 400/2000
= <u>0.2 m/s²</u>
<u />
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
Learn more about acceleration here:- brainly.com/question/29110429
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It should be at about 65J. Not sure, hope I helped.
