A volleyball is hit straight up in

Physics

1 answer:

SpyIntel [72]3 years ago

4 0

Answer:

a. 0 m

Explanation:

Given:

v₀ = 7.35 m/s

a = -9.8 m/s²

t = 1.50 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (7.35 m/s) (1.50 s) + ½ (-9.8 m/s²) (1.50 s)²

Δx = 0 m

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The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

Explanation:

From Physics we get that expansion of the rod portion is found by this formula:

$\Delta l = \alpha\cdot l_{o}\cdot (T_{f}-T_{o})$ (Eq. 1)

Where:

$\Delta l$ - Expansion of the rod portion, measured in meters.

$\alpha$ - Linear coefficient of expansion for titanium, measured in $\frac{1}{^{\circ}C}$ .

$l_{o}$ - Initial length of the rod portion, measured in meters.

$T_{o}$ - Initial temperature of the rod portion, measured in Celsius.

$T_{f}$ - Final temperature of the rod portion, measured in Celsius.

If we know that $\alpha = 5\times 10^{-6}\,\frac{1}{^{\circ}C}$ , $l_{o} = 10\,m$ , $T_{o} = 0\,^{\circ}C$ and $T_{f} = 400\,^{\circ}C$ , the expansion experimented by the rod portion is: