Answer:
The current in the second wire is 8.33 A and the two currents are flowing in the opposite directions
Explanation:
Given that,
The separation between two long parallel wires, d = 2.5 cm
The force per unit length that each wire exerts on the other is, 
The current in one wire, 
(a) The force per unit length of the wire is given by :
On putting all the values we get :
So, the current in the second wire is 8.33 A.
(b) It is given that, both the wires repel each other, so the current in other wire is flowing in the opposite direction of the current in the first wire.
Hence, this is the required solution.
The EMF induced in the second coil is 43 Volts.
Michael Faraday was the first to discover electromagnetic induction back in the 1830s. Faraday discovered that moving a permanent magnet in and out of a coil or a single loop of wire caused an electromotive force, or EMF—otherwise known as a voltage—to be produced.
Changing magnetic flux results in varied currents flowing through the coil, which in turn generates its own magnetic field. This self-induced EMF opposes the change that is creating it, and the stronger the opposing EMF is, the faster the rate at which the current is changing. According to Lenz's law, this self-induced EMF will oppose the change in current in the coil, and because of its orientation, it is typically referred to as a back-EMF.
To learn more about EMF please visit-
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Answer:
a gravitational force is double
b gravitational force become 4 time
c gravitational force is reduced by 4
A jumble of relatively young volcanic debris, some of it located where it fell in Mount Hood’s eruptive past, some of it moved here by the colossal advance of the Newton Clark Glacier during the last ice age.
Newton Clark Moraine
As a result, the rocks making up the moraine are sharp and raw, not rounded, and the debris is largely unsorted. Giant boulders perch precariously atop loose rubble, making the moraine one of the most unstable places on the mountain.
Answer:
364.4 J
Explanation:
I = Moment of inertia of the forearm = 0.550 kgm²
v = linear velocity of the ball relative to elbow joint = 17.1 m/s
r = distance from the joint = 0.470 m
w = angular velocity
Using the equation
v = r w
17.1 = (0.470) w
w = 36.4 rad/s
Rotational kinetic energy of the forearm is given as
RKE = (0.5) I w²
RKE = (0.5) (0.550) (36.4)²
RKE = 364.4 J
