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inna [77]
2 years ago
14

A rug sits in a sunny place on the floor for a long time. Kiara thinks that light from the sun can cause the rug's color to fade

over time. Can light from the sun cause the rug's color to fade?
Physics
1 answer:
geniusboy [140]2 years ago
3 0

Answer:

Yes! Light from the sun can affect the materials certain carpets are made out of. The usual effect being the dye in the carpet being "washed out" or "dried out" as the sun beams down on it. When this happens, the carpet will usually lose its color, causing it to fade.

You might be interested in
The diagram below shows the velocity vectors for two cars that are moving relative to each other.
scoundrel [369]

Answer:

The answer is "5 \ \frac{m}{s} \ west"

Explanation:

\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to  \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\

velocity of car | respect to car :

\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\

          =\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west

7 0
3 years ago
A car is designed to get its energy from a rotating flywheel with a radius of 1.50 m and a mass of 430 kg. Before a trip, the fl
fiasKO [112]

Answer:

a

  KE  =  7.17 *10^{7} \ J

b

 t = 6411.09 \ s

Explanation:

From the question we are told that

    The radius of the flywheel is  r =  1.50 \ m

      The mass of the flywheel is m  = 430 \ kg

          The rotational speed of the flywheel is w  =  5,200 \ rev/min = 5200 *  \frac{2 \pi }{60} =544.61 \ rad/sec

      The power supplied by the motor is  P  =  15.0 hp =  15 * 746 =  11190 \ W

         

     Generally the moment of inertia of the flywheel is  mathematically represented as

       I  = \frac{1}{2} mr^2

substituting values

       I  = \frac{1}{2}  ( 430)(1.50)^2

       I  = 483.75 \  kgm^2

The kinetic energy that is been stored is  

       KE  =  \frac{1}{2} * I * w^2

substituting values

        KE  =  \frac{1}{2} * 483.75 * (544.61)^2

        KE  =  7.17 *10^{7} \ J

Generally power is mathematically represented as

          P =  \frac{KE}{t}

=>      t =  \frac{KE}{P}

substituting the value

        t = \frac{7.17 *10^{7}}{11190}

        t = 6411.09 \ s

3 0
3 years ago
If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
vaieri [72.5K]

The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

\mu_0= magnetic permeability

= 4\pi×10⁻⁷ H m⁻¹

If= 12 A

d= distance from each wire to point.

=0.12m

Now we put the known values in the above equation, we get

F= \frac{\mu_0 I_f}{2\pi d}

Or, F = \frac{4\pi \times 10^{-7}\times  12}{2\pi \times 0.12}

Or, F= 2×10⁻⁵ N/m.

From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.

Learn more about magnetic force:

brainly.com/question/2279150

#SPJ4

7 0
1 year ago
An alpha particle(the nucleus of a helium atom) has a mass of 6.64*10^-27kg and a charge of +2e. What are the magnitude and dire
emmasim [6.3K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Weight = electric force 
<span>mg = qE </span>

<span>6.64x10^-27 x 9.81 = (2 x 1.60x10^-19) E 
</span>qE =mg, 
<span>E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m</span>
8 0
3 years ago
Read 2 more answers
A uniform magnetic field of magnitude 0.72 T is directed perpendicular to the plane of a rectangular loop having dimensions 8.2
Liono4ka [1.6K]

Answer:

Explanation:

Magnetic flux is expressed as the product of magnetic field and cross sectional area.

Φ = BAsintheta

Given

B = 0.72T

A = 8.2cm×14cm

A = 0.082m × 0.14m

Area = 0.01148m²

Theta = 90°

Substitute into the formula

Φ = BAsintheta

Φ = 0.72(0.01148)sin90°

Φ = 0.72(0.01148)(1)

Φ = 0.0082656

Hence the magnetic flux through the loop is 8.2656 × 10^-3 Weber

8 0
3 years ago
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