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kaheart [24]
3 years ago
11

A mining crew extracted two different types of minerals from underground. Then, they transferred the same amount of energy into

both minerals. Why did mineral A change while mineral B stayed the same? Explain what happened to the molecules of both minerals
Physics
2 answers:
Harrizon [31]3 years ago
6 0

Answer:  Sorry i don't know the answer

Explanation:

statuscvo [17]3 years ago
5 0

Answer:

sorry but i dont know

Explanation:

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Round the following off to required number of significant figures.
Stells [14]

Answer:

140

hope this helps

have a good day :)

Explanation:

4 0
2 years ago
Read 2 more answers
There is up to 30 times more gold in a tons of old mobile phones than in a tons of gold ore. true or false
FrozenT [24]

Answer:

true

Explanation:

dbgkdodocofkci ifkdcl k kfododocp v

3 0
2 years ago
To determine a waves' frequency, you must know the
givi [52]
The correct answer is<span> number of oscillations in a given period of time

This is measured in what is called the Hertz measurement and the period of time is usually taken to be per second.</span>
6 0
3 years ago
The electric motor of a model train accelerates the train from rest to 0.620 m/s in 21ms. The total mass of the train is 825 g.
Rudiy27

Explanation:

Average power = change in energy / change in time

P = ΔE / Δt

P = (½ mv²) / t

P = (½ (0.825 kg) (0.620 m/s)²) / (0.021 s)

P = 7.55 Watts

7 0
2 years ago
A lead ball is dropped into a lake from a diving board 5.0 m above the water. After entering the water, it sinks to the bottom w
nirvana33 [79]

Answer:

|D_{depth} |=19.697m

Explanation:

To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:

Δx=vit+(1/2)at²

x_{f}-x_{i}=v_{i}t+(1/2)at^{2}\\  -5.0m=(o)t+(1/2)(-9.8m/s^{2} )t^{2}\\ -4.9t^{2}=-5.0\\ t^{2}=5/4.9\\t=\sqrt{1.02} \\t=1.01s

As we have find the time taken now we need to find the final velocity vf from below equation as

v_{f}=v_{i}+at\\v_{f}=0+(-9.8m/s^{2} )(1.01s) \\v_{f}=-9.898m/s

So the depth of lake is given by:

first we need to find total time as

t=3.0-1.01 =1.99 s

|D_{depth} |=|vt|\\|D_{depth} |=|(-9.898m/s)(1.99s)|\\|D_{depth} |=19.697m

6 0
3 years ago
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