Let <em>w</em> denote the weight of the sofa, <em>n</em> the magnitude of the normal force, and <em>f</em> the magnitude of the friction force. The sofa is in equilibrium, so by Newton's second law,
<em>n</em> - <em>w</em> = 0
125 N - <em>f</em> = 0
The sofa has a weight of
<em>w</em> = (132 kg) <em>g</em> = 1293.6 N
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Since <em>n</em> = <em>w</em>, the normal force has the same magnitude.
The friction force is proportional to the normal force by a factor of the coefficient of static friction <em>µ</em>, such that
<em>f</em> = <em>µ</em> <em>n</em>
Our second equation tells us <em>f</em> = 125 N, so solve for <em>µ</em> :
125 N = <em>µ</em> (1293.6 N)
<em>µ</em> ≈ 0.0966
Answer:
The speed of the rock when it is at height h/4 is
.
Explanation:
At maximum height the final velocity of the rock is equal to 0. Let u is the initial velocity of the rock. Using the conservation of energy to find it as :
.......(1)
We need to find the speed of the rock when it is at height h/4. Let v' is the speed. Using 3rd equation of motion as :

here a = -g and s = h/4

Using equation (1) :

So, the speed of the rock when it is at height h/4 is
. Hence, this is the required solution.
The distance between city a and city b is 833.345 miles.
We know that
1°=60'
The distance of city a from the initial ray is calculated as
x_a=3960*tan45.46°=4024.101 miles
The distance of city b from the initial ray is calculated as
x_b=3960*tan 38.86°=3190.75 miles
Now the distance between city a and b is equal to
4024.101-3190.75=833.345 miles
This is the vertical distance between the cities.
Answer:
The answer is A , aka, a reflector that is bright color and smooth
Explanation:
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