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disa [49]
2 years ago
11

What did johannes kepler contribute to the study of planets? he formulated the universal law of gravitation. he identified the f

irst moons of jupiter. he collected detailed data that led to the proposal of the heliocentric model. he provided mathematical support for the heliocentric model.
Physics
1 answer:
Deffense [45]2 years ago
7 0

Johannes Kepler contributed to the study of planets : He provided mathematical support for the heliocentric model.

<h3>What is Kepler's first law of planetary motion?</h3>

Kepler's first law of planetary motion states that the planets revolve around the Sun in orbits elliptical in shape with the Sun at its one of the focus.

As the planets rotate around the Sun, the relative distance between the Sun and planets increases and decreases.

The heliocentric model in which the Earth and planets revolve around the Sun at the center of the universe. Johannes gave the mathematical calculations of this model.

Thus, last option is correct.

Learn more about Kepler's first law of planetary motion.

brainly.com/question/4978861

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What is matter made of ? Will mark as brainliest to answer
Masja [62]

Answer:

Explanation:

All matter is made up of atoms, which are turned up of protons, neutrons and electrons.

They bond together to make up matter

8 0
3 years ago
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As Earth moves around the Sun, its _____ is approximately perpendicular to the force of gravity exerted by the Sun.
Bogdan [553]

SORRY i forgot but i think its A because the sun has a really strong gravitational pull


sorry and hope it helps

4 0
2 years ago
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Kepler’s third law can be used to derive the relation between the orbital period, P (measured in days), and the semimajor axis,
NikAS [45]
Kepler's 3rd law is given as
P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant

Given:
P = 687 days
A = 1.52 AU

Therefore
k = P²/A³ = 687²/1.52³ = 1.3439 x 10⁵ days²/AU³

Answer:  1.3439 x 10⁵ (days²/AU³)

8 0
3 years ago
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a projectile is launched at an angle of 30 degrees and lands later at the same level. if it's initial speed is 50 m/s, solve for
Mrrafil [7]
using \: the \: formula \\ t = \frac{2u \sin( \alpha ) }{g} where \: u = initial \: speed \: \\ \alpha = angle \: of \: projection \\ g = acceleration \: due \: to \: gravity \\ \frac{2 \times 50 \times \sin(30) }{10} \\ \frac{100 \times 0.5}{10} = \frac{50}{10} = 5seconds

Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
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3 0
2 years ago
As a physics instructor hurries to the bus stop, her bus passes her, stops ahead, and begins loading passengers. She runs at 6.0
Alika [10]

velocity of the physics instructor with respect to bus

v = 6 m/s

acceleration of the bus is given as

a = 2 m/s^2

acceleration of instructor with respect to bus is given as

a = -2 m/s^2

now the maximum distance that instructor will move with respect to bus is given as

v_f^2 - v_i^2 = 2 a d

0 - 6^2 = 2(-2)(d)

-36 = - 4 d

d = 9 m

so the position of the instructor with respect to door is exceed by

\delta x = 9 - 6 = 3 m

so it will be moved maximum by 3 m distance

7 0
3 years ago
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