1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
disa [49]
2 years ago
11

What did johannes kepler contribute to the study of planets? he formulated the universal law of gravitation. he identified the f

irst moons of jupiter. he collected detailed data that led to the proposal of the heliocentric model. he provided mathematical support for the heliocentric model.
Physics
1 answer:
Deffense [45]2 years ago
7 0

Johannes Kepler contributed to the study of planets : He provided mathematical support for the heliocentric model.

<h3>What is Kepler's first law of planetary motion?</h3>

Kepler's first law of planetary motion states that the planets revolve around the Sun in orbits elliptical in shape with the Sun at its one of the focus.

As the planets rotate around the Sun, the relative distance between the Sun and planets increases and decreases.

The heliocentric model in which the Earth and planets revolve around the Sun at the center of the universe. Johannes gave the mathematical calculations of this model.

Thus, last option is correct.

Learn more about Kepler's first law of planetary motion.

brainly.com/question/4978861

#SPJ1

You might be interested in
I need help with this question how to solve it for Brass and Cooper
Ksenya-84 [330]

Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

3 0
1 year ago
For a vehicle to negotiate a banked curve in poor weather conditions, where the force of friction f = 0, for a given velocity v
djverab [1.8K]

Answer:

R=240m

Explanation:

From the question we are told that:

Velocity v=25m/s

Force of friction f = 0

Angle \theta=15

Generally the equation for  Radius of curvature is mathematically given by

R=frac{v^2}{tan\theta *g}

R=frac{25^2}{tan 15 *9.81}

R=240m

7 0
3 years ago
A proton is released in a uniform electric field, and it experiences an electric force of 2.04×10−14 N toward the south.
Lemur [1.5K]

Answer:

Part A:

E=127500N/C\\E=1.275*10^{5} N/C

Part B:

Option B (Towards the South)

Explanation:

Part A:

Magnitude if electric field E:

E=Force/charge

Force=2.04×10−14 N

Charge=1.6×10−19 C

E=\frac{2.04*10^{-14}}{1.6*10^{-19}} \\E=127500N/C\\E=1.275*10^{5} N/C

Part B:

Option B (Towards the South)

As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.

7 0
3 years ago
In the aerials competition in skiing, the competitors speed down a ramp that slopes sharply upward at the end. The sharp upward
11111nata11111 [884]

Answer:

u = 11.6 m/s

Explanation:

The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.

Maximum height, H = 10.9

Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :

H=\dfrac{u^2\ sin^2\theta}{g}

10.9=\dfrac{u^2\ sin^2(63)}{9.8}

u = 11.6 m/s

So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.

4 0
3 years ago
Which is a heterogeneous mixture?
lesya [120]

Answer:

eat my gunterxtrappin

Explanation:

7 0
3 years ago
Other questions:
  • A 68.5 kg astronaut is doing a repair in space on the orbiting space station. she throws a 2.25 kg tool away from her at 3.20 m/
    6·1 answer
  • Nuclear fission can be described as a chain reaction.<br> a. True<br> b. False
    13·2 answers
  • Astronomers use the _______ of stars to determine how hot they are and their _______ to estimate how far away they are. A. brigh
    6·1 answer
  • YALLL I NEED HELP ASAP... THIS DUE AT 11:59 AND ITS 10.42 RIGHT NOW
    12·1 answer
  • You have 750 g of water at 10°C in a large insulated beaker. How much boiling water at 100°C must you add to this beaker so that
    7·1 answer
  • Why doesnt the moon crash towards earths surface?
    15·2 answers
  • A 1.0μF capacitor with an initial stored energy of 0.50 J is discharged through a 1.0MΩ resistor. (a) What is the initial charge
    11·1 answer
  • Here's the cbse syllabus for magnetic effects of electric current​
    15·1 answer
  • Need help guys please
    11·1 answer
  • Define force ? ☹❣️️ Degine weight? ​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!