Question

Horace has invented a unique pair of reading glasses that have two small light bulbs at the bottom wired in series, so that he can see the newspaper when he is reading at night. Each of the bulbs has a resistance of 2.00 , and the system runs off a 3.20-V battery. How much current is drawn by Horace’s reading glasses?

Answer 1

Answer:

The current drawn by Horace’s reading glasses is 0.8 A.

Explanation:  

Given that,

Resistance of each bulb, R = 2 ohms

Voltage of the system, V = 3.2 volts

These two bulbs are connected in series. The equivalent resistance will be 2 ohms +2 ohms = 4 ohms

Let I is the current drawn by Horace’s reading glasses. Using Ohm's law to find it such that :

$V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{3.2}{4}\\\\I=0.8\ A$

So, the current drawn by Horace’s reading glasses is 0.8 A.