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Dmitriy789 [7]
3 years ago
11

A car is moving with a velocity of45m/s. Is brought to rest in 5s.the distance travelled by car before it comes to rest is

Physics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

The car travels the distance of 225m before coming to rest.

Explanation:

Here,

v = 45m/s

t = 5s

d = v × t

Therefore,

d = 45 × 5

= 225m

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Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
g100num [7]

I have attached the image showing the 6 combination of charges

Answer:

Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc

Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc

Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc

Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc

Explanation:

The electrostatic force between 2 charges is; F = k•q1•q2/r²

Where r is the distance between the 2 charges q1 and q2 and k is coulombs constant.

Thus;

F ∝ q1•q2/r²

The net force on the charge q1 is the sum of the forces on charge q2 and q3.

If the two charges are opposite, the force is an attractive force while if the two charges are similar, the force is a repulsive force.

Thus, if the combination has same type of charges, i.e;(+1,+1,+1) or (-1,-1,-1), the force will be very small.

So, now the order of forces from smallest to largest is;

Smallest are: q1 = +1 nc, q2 = +1 nc, q3 = +1 nc and q1 = -1 nc, q2 = -1 nc, q3 = -1nc

Third Largest: q1 = +1 nc, q2 = +1nc, q3 = -1 nc

Second Largest: q1 = +1 nc, q2 = -1 nc, q3 = +1 nc

Largest are: q1 = +1 nc, q2 = -1 nc, q3 = -1 nc and q1 = -1 nc, q2 = +1 nc, q3 = +1 nc

3 0
3 years ago
When you hear a noise, you usually know the direction from which it came even if you cannot see the source. This ability is part
adelina 88 [10]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

3 0
3 years ago
A car changes velocity at a constant acceleration of 2.5m/s to reach 43.7m/s in 2.7 s how fast was the car moving when it began
Montano1993 [528]

The formula we can use in this case is:

v = v0 + a t

where v is final velocity, v0 is initial velocity, a is acceleration and t is time

So finding for v0:

v0 = v – a t

v0 = 43.7 – (2.5) 2.7

v0 =  36.95 m/s

8 0
3 years ago
Which set of terms is in the proper order, from left to right, for labeling the
Rufina [12.5K]
A. Base , salt , water,acid
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2 years ago
A lightning bolt with 13 kA strikes an object for 14 μ s. How much charge is deposited on the object?
pogonyaev

Answer:

0.182C

Explanation:

Using Q= It

= 13x10^3 . 14x10^-6

= 0.182C

8 0
3 years ago
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