the table below:
Grade In favor Opposed Undecided Total
Grade 9 6 4 8 18
Grade 10 10 11 9 30
Grade 11 12 15 11 38
Grade 12 15 6 14 35
If the principal randomly selects a student in grade 10 from this survey,
the probability that the student is opposed to extending the school day
P ( student in grade 10 is opposed)= Number of student in opposed(grade10) / total number of students in grade 10
Number of student opposed who is in grade10 = 11
total number of students in grade 10 = 30
P( student in grade 10 is opposed)= 
= 0.37
the probability that the student is opposed to extending the school day= 0.37
Thanks for posting your question here. The answer to the above problem is x = <span>48.125. Below is the solution:
</span>
x+x/7+1/11(x+x/7)=60
x = x/1 = x • 7/7
x <span>• 7 + x/ 7 = 8x/7 - 60 = 0
</span>x + x/7 + 1/11 <span>• 8x/7 - 60 = 0
</span>8x <span>• 11 + 8x/ 77 = 96x/ 77
</span>96x - 4620 = 12 <span>• (8x-385)
</span>8x - 385 = 0
x = 48.125
40(12.62) + 7(12.62(1.5)) = 504.80 + 7(18.93) = 504.80 + 132.51 =
637.31 <===
Answer:
y = 1/9
Step-by-step explanation:
(-2, y) = (x, y)
y = 3^x
y = 3^(-2)
y = 1/9
Therefore y = 1/9