Answer:
don't know
Explanation:
can you give the other parts of the question?
To solve this problem it is necessary to apply the concepts related to the magnetic flow of a coil and take into account the angles for each case.
It is also necessary to delve into part C, the concept of electromotive force (emf) which is defined as the variation of the magnetic flux as a function of time.
By definition the magnetic flux is determined as:
![\phi = NBA cos\theta](https://tex.z-dn.net/?f=%5Cphi%20%3D%20NBA%20cos%5Ctheta)
Where
N = Number of loops
We will calculate the value for each of the spins
B = Magnetic Field
A = Cross-sectional Area
Angle between the perpendicular cross-sectional area and the magnetic field.
PART A) The magnetic flux through the coil after it is rotated is as follows:
![\phi_i = NBA cos\theta](https://tex.z-dn.net/?f=%5Cphi_i%20%3D%20NBA%20cos%5Ctheta)
![\phi_i = (1turns)(6*10^{-5}T)(12*10^{-4}m^2)cos(0)](https://tex.z-dn.net/?f=%5Cphi_i%20%3D%20%281turns%29%286%2A10%5E%7B-5%7DT%29%2812%2A10%5E%7B-4%7Dm%5E2%29cos%280%29)
![\phi_i = 7.2*10^{-8}T\cdot m^2](https://tex.z-dn.net/?f=%5Cphi_i%20%3D%207.2%2A10%5E%7B-8%7DT%5Ccdot%20m%5E2)
PART B) For the second case the angle formed is perpendicular therefore:
![\phi_f = NBA cos\theta](https://tex.z-dn.net/?f=%5Cphi_f%20%3D%20NBA%20cos%5Ctheta)
![\phi_f = (1turns)(6*10^{-5}T)(12*10^{-4}m^2)cos(90)](https://tex.z-dn.net/?f=%5Cphi_f%20%3D%20%281turns%29%286%2A10%5E%7B-5%7DT%29%2812%2A10%5E%7B-4%7Dm%5E2%29cos%2890%29)
![\phi_f = 0](https://tex.z-dn.net/?f=%5Cphi_f%20%3D%200)
PART C) The average induced emf of the coil is as follows:
![\epsilon = - (\frac{\phi_f-\phi_i}{dt})](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%20%28%5Cfrac%7B%5Cphi_f-%5Cphi_i%7D%7Bdt%7D%29)
![\epsilon = -(\frac{0-7.2*10^{-8}}{0.04})](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%28%5Cfrac%7B0-7.2%2A10%5E%7B-8%7D%7D%7B0.04%7D%29)
![\epsilon = 1.8*10^{-6}V](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%201.8%2A10%5E%7B-6%7DV)
Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that
![-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}](https://tex.z-dn.net/?f=-%5Cint%5Climits%5Ea_b%20%5Cvec%7BE%7Dd%5Cvec%7Bl%7D%20%3D%20V_%7Bab%7D)
Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:
![V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon_0%7D%5Cfrac%7Bq%7D%7Br%5E2%7D)
There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.
Answer:
B. Golgi body
Explanation:
The Golgi body is the region where proteins are modified, packaged, and transported to the appropriate location, usually outside of the cell.
The cytoplasm is the intracellular fluid/space, the mitochondrion produces energy, the ribosome produces proteins, and the vacuole is a storage organelle.