What would happen if friction suddenly disappears while you are driving a car? (full explanation)

The paper dielectric in a paper-and-foil capacitor is 0.0800 mm thick. Its dielectric constant is 2.50, and its dielectric stren

jeka94

Answer:

a) 0.723 m²

b) 2000V

Explanation:

Given that

Thickness of the capacitor, d = 0.08*10^-3 m

Dielectric constant of the capacitor, k = 2.5

Dielectric strength of the capacitor, E = 50*10^6

Capacitance of the capacitor, C = 0.2*10^-6

Permittivity of free space, E• = 8.85*10^-12

a)

The area, A is given by the formula

A = (C * d) / (k * E•)

A = (0.2*10^-6 * 0.08*10^-3) / (2.5 * 8.85*10^-12)

A = 1.6*10^-11 / 2.213*10^-11

A = 0.723 m²

b)

Potencial difference, V is given by the formula

V = E * d

V = 1/2 * 50*10^6 * 0.08*10^-3

V = 1/2 * 4000

V = 2000 V

8 0

4 years ago

Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init

Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ= $(m+\frac{1}{2})\frac{lamda}{n}$ ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= $\frac{3*lamda}{2}$

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= $\sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }$

δ= $\sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}$

δ= $\sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }$

δ= $\sqrt{4900+43^2}-\sqrt{4900+23^2}$

δ= $\sqrt{4900+1849}-\sqrt{4900+529}$

δ= $\sqrt{6749}-\sqrt{5429}$

δ= 82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= $\frac{3*lamda}{2}$

δ= 8.47

8.47 = $\frac{3*lamda}{2}$

λ = $\frac{8.47*2}{3}$

λ = 5.65m

3 0

4 years ago

Determine the values of mm and nn when the following average magnetic field strength of the Earth is written in scientific notat

joja [24]

Answer:

m = 4.51 and n = -5

Explanation:

The average magnetic field strength of the Earth is 0.0000451 T. We need to write the value of magnetic field strength of the Earth in scientific notation. In scientific notation, any value is given by :

$N=m\times 10^n$ .........(1)

Where

m is a real number

n is any integer

Here,

$N=4.51\times 10^{-5}$ .......(2)

On comparing equation (1) and (2), we get the values as :

m = 4.51 and n = -5

Hence, this is the required solution.

6 0

3 years ago

A 60 W light bulb has a resistance of 880 Ω

Andreas93 [3]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf{• \: Power \: (P) = 60 \: w}$

$\sf{• \: Resistance \: (R) = 880 \: Ω}$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf• \: The \: Current \: (I).$

$\\$

$\huge\bf{ \underline{ Solution :- }}$

$\sf We \: know \: that,$

$\bf \red {\bigstar{ \: P = I^{2} R}}$

$\rightarrow \sf 60 = I^{2} \times 880$

$\rightarrow \sf \frac{60}{880} = I^{2}$

$\rightarrow \sf I^{2} = 0.0681$

$\rightarrow \sf I = \sqrt{0.0681}$

$\rightarrow \sf I = 0.261 \: \: (approx.)$

$\\$

$\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)$

7 0

3 years ago

Calculate the work done on a Pressure / Volume (PV) isothermal expansion where 400 Pa and 0.08 volume in m3?

Ainat [17]

PV = 400 x 0.08 = 32 J

Hope this helps

7 0

3 years ago