The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2 
Since the Ms are the same, then 
2mx^2 / L^2 = m(L - x)^2 / L^2 
2x^2 = (L - x)^2 
xsqrt2 = L - x 
x(1 + sqrt2) = L 
x = L / (sqrt2 + 1) From here, we rationalize. 
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1) 
x = L(sqrt2 - 1) / (2 - 1) 
x = L(sqrt2 - 1) </span>
 
= 0.414L
 
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
 
        
             
        
        
        
No,because they  may have more particles 
        
             
        
        
        
Answer: Yes the further the sun is away the longer the shadow is. At noon,the shadow is the shortest because its straight up above you. If this helps pls mark brainliest!