1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
6

Sound travels through air at 343 m/s,

Physics
1 answer:
sasho [114]3 years ago
5 0

The sound wave will have traveled 2565 m  farther in water than in air.

Answer:

Explanation:

It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.

Distance = Velocity × Time.

So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.

As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.

Distance = 343 × 2.25 =771.75 m

And for the sound wave travelling in fresh water, the velocity is given as 1483 m/s. So in a time interval of 2.25 s, the distance can be determined as the product of velocity and time.

Distance = 1483×2.25=3337 m.

Since, the velocity of sound wave travelling in fresh water is greater than the sound wave travelling in air, the distance traveled by sound wave in fresh water will be greater.

Difference in distance covered in water and air = 3337-772 m = 2565 m

So the sound wave will have traveled 2565 m  farther in water than in air.

You might be interested in
I’ve already figured out A. I just need help with B and C.
Damm [24]

Answer:

595433.00

1456543.00

Explanation:

7 0
3 years ago
A source at rest emits light of wavelength 500 nm. When it is moving at 0.90c toward an observer, the observer detects light of
Vesna [10]

Answer:

The observer detects light of wavelength is 115 nm.

(b) is correct option

Explanation:

Given that,

Wavelength of source = 500 nm

Velocity = 0.90 c

We need to calculate the wavelength of observer

Using Doppler effect

\lambda_{o}=\sqrt{\dfrac{1-\beta}{1+\beta}}\lambda_{s}

Where, \beta=\dfrac{c}{v}

\lambda_{o}=\sqrt{\dfrac{c-0.90c}{c+0.90c}}\times500\times10^{-9}

\lambda_{o}=115\ nm

Hence, The observer detects light of wavelength is 115 nm.

8 0
3 years ago
Rodrigo wants to find more ways to improve his latest design. Which of the following should he try?
irina [24]

Answer: ask other people if they like it, or ask what they want to add

Explanation: because maybe other people can can help him improve and brainstorm with other’s.

5 0
3 years ago
Read 2 more answers
Two transverse waves travel along the same taut string. Wave 1 is described by y1(x, t) = A sin(kx - ωt), while wave 2 is descri
Vadim26 [7]

Answer:

6) Wave 1 travels in the positive x-direction, while wave 2 travels in the negative x-direction.

Explanation:

What matters is the part kx \pm \omega t, the other parts of the equation don't affect time and space variations. We know that when the sign is - the wave propagates to the positive direction while when the sign is + the wave propagates to the negative direction, but <em>here is an explanation</em> of this:

For both cases, + and -, after a certain time \delta t (\delta t >0), the displacement <em>y</em> of the wave will be determined by the kx\pm\omega (t+\delta t) term. For simplicity, if we imagine we are looking at the origin (x=0), this will be simply \pm \omega (t+\delta t).

To know which side, right or left of the origin, would go through the origin after a time \delta t (and thus know the direction of propagation) we have to see how we can achieve that same displacement <em>y</em> not by a time variation but by a space variation \delta x (we would be looking where in space is what we would have in the future in time). The term would be then k(x+\delta x)\pm\omega t, which at the origin is k \delta x \pm \omega t. This would mean that, when the original equation has kx+\omega t, we must have that \delta x>0 for k\delta x+\omega t to be equal to kx+\omega\delta t, and when the original equation has kx-\omega t, we must have that \delta x for k\delta x-\omega t to be equal to kx-\omega \delta t

<em>Note that their values don't matter, although they are a very small variation (we have to be careful since all this is inside a sin function), what matters is if they are positive or negative and as such what is possible or not .</em>

<em />

In conclusion, when kx+\omega t, the part of the wave on the positive side (\delta x>0) is the one that will go through the origin, so the wave is going in the negative direction, and viceversa.

4 0
3 years ago
Why would north america will not be able to view the eclipse
Flauer [41]

The North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

<h3>Effect of tilting of the Earth</h3>

The tilt of the Earth is what causes seasons to occur. These are the seasons in relation to the Northern Hemisphere.

The tilting of the Earth causes the difference in the amount of sun reaching each region of the earth like in the North America continent.

Thus, the North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

Learn more about eclipse here: brainly.com/question/8643

#SPJ1

4 0
2 years ago
Other questions:
  • PLZ HELP!!!!!!!
    9·2 answers
  • A laser beam of wavelength 439.4 nm is inci- dent on two slits 0.306 mm apart.
    6·1 answer
  • Anyone! Help me! (:o
    5·2 answers
  • What can you compare to 40 newtons of force??
    9·1 answer
  • Why does the unit of time enter twice in the unit of acceleration?
    5·1 answer
  • The features of Mercury are named in honor of famous people in which fields of endeavor?
    13·1 answer
  • Identify which objects will accelerate to the left, which will accelerate to the right,and those that will not accelerate. Optio
    15·1 answer
  • At what phase or phases could water exist at 4.579mm pressure and 0.0098°C?
    10·1 answer
  • To appreciate the strength of gravity, calculate the number of steel cables that would be required, in the absence of gravity, t
    7·1 answer
  • Cyclist A and B cycled atan average speed of 15 km/h and 20 km/h respectively from the same starting point X on the same route.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!