The static friction exerted on the block by the incline is 
.
The given parameters;
- <em>mass of the block, = M</em>
- <em>coefficient of static friction in section 1, = </em>
<em /> - <em>angle of inclination of the plane, = θ</em>
<em />
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
Thus, the static friction exerted on the block by the incline is
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Answer:
True
Explanation:
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Answer:
P = 16,000 kgm/s
Explanation:
<u><em>Given :</em></u>
Mass = m = 800 kg
Velocity = v = 72 km/hr = 20 m/s
<u><em>Required :</em></u>
Momentum = P = ?
<u><em>Formula:</em></u>
P = mv
<u><em>Solution:</em></u>
P = (800)(20)
P = 16,000 kgm/s
