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jasenka [17]
3 years ago
7

Question Please

TexFormula1" title="5 \frac{3}{4} \div 1 \frac{1}{2} " alt="5 \frac{3}{4} \div 1 \frac{1}{2} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0
The answer is 23/6 or 3.83333333
Marta_Voda [28]3 years ago
4 0
Either 23/6 or 3.83 with the 3 being repeated
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Kim had 12 cookies that brought to school she gave some cookies to her friends if Kim has no more than five cookies left how man
nalin [4]

Answer:

7

Step-by-step explanation:

12-5 = 7

7 0
2 years ago
Refer to the accompanying data set and construct a ​% confidence interval estimate of the mean pulse rate of adult​ females; the
ivolga24 [154]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval of mean pulse rate for adult female is 71.98 <  \mu <  79.88

The 95% confidence interval of mean pulse rate for adult male is  62.89 <  \mu <  70.57

The correct option is  C

Step-by-step explanation:

  Generally the sample mean for Male pulse rate is mathematically represented as

       \= x_1   = \frac{\sum x_i }{n}

= >    \= x_1   = \frac{81 + 74 + \cdots + 59 }{40 }

= >    \= x_1   = 66.73

Generally the standard deviation for male pulse rate is mathematically represented as

      \sigma_1 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }

=>   \sigma_1 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (74 - 66.73 )^2+ \cdot + (59 - 66.73 )^2 }{40-1 } }

=>   \sigma_1 = 12.24

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma_1 }{\sqrt{n} }

=>    E = 1.96 *  \frac{12.4 }{\sqrt{40} }

=>    E =3.84

Generally 95% confidence interval is mathematically represented as  

      \= x_1 -E <  \mu <  \=x_1  +E

=>    66.73 -3.84 <  \mu < 66.73 +3.84

=>    62.89 <  \mu <  70.57

  Generally the sample mean for Female pulse rate is mathematically represented as

       \= x_2   = \frac{\sum x_i }{n}

= >    \= x_2   = \frac{81 + 94 + \cdots + 73 }{40 }

= >    \= x_2   = 75.93

Generally the standard deviation for Female  pulse rate is mathematically represented as

      \sigma_2 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }

=>   \sigma_2 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (94 - 66.73 )^2+ \cdot + (73 - 66.73 )^2 }{40 } }

=>   \sigma_2 = 12.73

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma_2 }{\sqrt{n} }

=>    E = 1.96 *  \frac{12.73 }{\sqrt{40} }

=>    E =3.95

Generally 95% confidence interval is mathematically represented as  

      \= x_2 -E <  \mu <  \=x_2  +E

=>    75.93 -3.95 <  \mu < 75.93 + 3.95

=>    71.98 <  \mu <  79.88

8 0
2 years ago
Which are correct representations of the inequality 6x &gt; 3 + 4/2x-112 Select three options
cricket20 [7]

Answer:

The Third one

Step-by-step explanation:

-2x>-1

x<1\2 Because when you divide by negative the symbol is changed.

4 0
3 years ago
Algebra 1 brainilest if correct and reported if not answered.
svlad2 [7]
The answer is D :) hope this helped
3 0
2 years ago
At the fundraiser, Chad washed 7 cars every 3 hours and earned over $150 for the school dance. 3. Choose the correct answer. Whi
Vladimir [108]

Answer:

the answer is 22

Step-by-step explanation:

4 0
2 years ago
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