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uysha [10]
3 years ago
9

The main reasons why ch4 has a higher vapor pressure at a given temperature when compared to ch3cl is that ch4 and . 2. the main

reasons why h2co has a higher vapor pressure at a given temperature when compared to ch3oh is that h2co and . 3. the main reason why ch3oh has a higher vapor pressure at a given temperature when compared to ch3ch2ch2oh is that ch3oh .
Chemistry
1 answer:
ale4655 [162]3 years ago
8 0
Vapour pressure of system depends upon intermolecular forces of interaction. Greater the interaction, larger will the vapour pressure, more will be the boiling point.

Answer 1: 
CH4 stands for methane and CH3Cl named as chloromethane. In methane, all the valances of C atom is satisfied by hydrogen. Due to this, it has zero dipole moment. While, in case of CH3Cl, one of the valance is satisfied by an electronegative element i.e. Cl. Due to this, it acquires a polar character. Also, it has a net dipole moment. Due to this, CH3Cl exhibits dipole-dipole intermolecular force of attraction, which is absent in CH4.  Hence, CH3Cl has lower vapor pressure as compared to CH4. 

Answer 2: 
H2CO is named as formaldehyde, while CH3OH is named as methyl alcohol. In case of methyl alcohol, hydrogen atom (an electropositive atom) is bonded to oxygen (a highly electronegative element). This is absent in case of formaldehyde. Due the this, methyl alcohol as greater polarity as compared to formaldehyde. Due the greater polarity, vapour pressure of CH3OH is less as compared to H2CO. 

Answer 3:
<span>CH3CH2CH2OH is named as propanol or propyl alcohol. Propyl alcohol, has longer chain length as compared to methyl alcohol (CH3OH). Both of this compounds has a polar character due to presence of -OH functional group. However, due to long chain of propyl alcohol, polar character increases. This can be attributed the +I effect of CH3 group. Due to this, intermolecular forces of interaction are higher in propanol, thereby decreasing its vapor pressure as compared to methanol. </span>
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When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is r
butalik [34]

Answer:

There is 78.25g NaHCO3 required

Explanation:

Step 1: Balance the equation

2 NaHCO3 → Na2CO3 + CO2 + H20

For 2 moles of NaHCO3 consumed, there is produced 1 mole of Na2CO3, 1 mole of CO2 and 1 mole of H2O.

Step 2: calculating moles of CO2

mass of Co2 = 20.5g

Molar mass of CO2 = 44.01 g/mole

moles of CO2 = 20.5 / 44.01 = 0.4658 moles

Step 3: Calculating moles of NaHCO3

Since we have for 1 mole CO2 produced, there is 2 moles of NaHCO3 consumed.

To calculate number of moles of NaHCO3, we have to multiply the number of moles of CO2, by 2.

⇒ 0.4658 x2 = 0.9316 moles

Step 4: Calculating the mass of NaHCO3

mass of NaHCO3 = moles of NaHCO3 x Molar mass of NaHCO3

mass = 0.9316 moles x 84g/ mole = 78.25g NaHCO3

There is 78.25g NaHCO3 required

4 0
3 years ago
What is the molarity of 62grams of ammonium in 5liters of water?
Viefleur [7K]

Answer:

Explanation:

First we need to find how many moles of ammonium weigh 62 grams.

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or 18.0 grams/mole

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If it is dissolved in 5 litres of water, the concentration will be 3.444moles/5L

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7 0
2 years ago
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3 0
2 years ago
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finlep [7]
This problem is very easy to answer. You simply have to look at the subscripts of each element of the compound.

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