Yea same I tried so hard I think you need to get a expert or look this up on a website or something
I think the chemical reaction is:<span>
N2H4 + 2 H2O2-> N2 + 4H2O
We are given the amount reactants allowed to react. This will be the starting point of the reaction. First, is to find the limiting reactant.
9.24 g H2O2 ( 1 mol / 34.02 g ) = 0.27 mol H2O2
6.56 g N2H4 ( 1mol / 32.06) = 0.20 mol N2H4
Since from the reaction we have 1:2 ratio of the reactants then the limiting reactant is hydrogen peroxide. We will use this to find the amount of N2 produced.
0.27 mol H2O2 ( 1 mol N2 / 2 mol H2O2 ) ( 14.01 g N2 / 1 mol N2) =1.89 g N2
</span>
The answer would be .40008L
The word milli- translates to
units. In this case, we have liters as our base unit. So a milliliter is
Liters or you can say that there are:
1,000 mL in 1 L.
As I understand, you are trying to convert 400.08mL to L.
So this is how you are going to get it:
x
=
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The concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.
<h3>What is the balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen?</h3>
The balanced equation for the decomposition of sulfur trioxide into sulfur dioxide and oxygen is given below as:
The addition of more sulfur trioxide to the bottle will result in increase in the volume of oxygen present as equilibrium will shift towards formation of products.
The addition of more sulfur dioxide to the bottle will result in decrease in the volume of oxygen present as equilibrium will shift towards formation of sulfur trioxide due to increase in product concentration.
Based on the graph, if the bottle is sealed, the concentration of sulfur trioxide will remain in dynamic equilibrium with the concentration of the products after the second day.
Based on the above information and reaction, the best way to reduce the amount of SO3 in the atmosphere, and thus reduce the amount of acid rain is to allow it to decompose before emission into the atmosphere,
Therefore, the concentration of the sulfur trioxide decreases with time due to its decomposition into sulfur dioxide and oxygen.
Learn more about sulfur trioxide decomposition at: brainly.com/question/10982712
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