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4 years ago

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A sample of argon at 300. °C and 50.0 atm pressure is cooled in the same container to a temperature of 0. °C. What is the new pr

essure, if the volume and amount of gas do not change?

2 answers:

Tresset [83]4 years ago

7 0

Answer: 105 atm

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$ (At constant volume and number of moles)

${P_1\times T_1}={P_2\times T_2}$

where,

$P_1$ = initial pressure of gas = 50 atm

$P_2$ = final pressure of gas = ?

$T_1$ = initial temperature of gas = $30^0c=(300+273)K=573K$

$T_2$ = final temperature of gas = $0^0c=(0+273)K=273K$

${50\times 573}={P_2\times 273}$

$P_2=105atm$

Therefore, the new pressure of the gas will be 105 atm.

Scrat [10]4 years ago

6 0

20.6031685 atm for the temperature

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Applying the equation of Arrhenius theory.

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