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3 years ago

Are nuclear bombs ethical? Explain please

Chemistry

2 answers:

Mrac [35]3 years ago

6 0

Answer:

Yes, they are.

Explanation:

The United States is one of these nuclear superpowers, making the ethical issues associated with these weapons critical and relevant. ... Most research across disciplines unanimously agrees that it is immoral to detonate an atomic weapon due to both short and long-term catastrophic effects.

In fact, some scholars have concluded that it is therefore morally wrong to act in ways that produce these outcomes, which means it is morally wrong to engage in nuclear warfare.

Paladinen [302]3 years ago

5 0

Answer:

NO not at all.

Explanation:

After reading the accounts of people who survived the bomb in Hiroshima and Nagasaki in 1945 during World War II, I was horrified just reading the testimonies. Almost every single survivor described the skinless and bloated bodies they had seen everywhere. Inosuke Hayasaki, a surivor of the bombing, noticed one of his classmates, among many other citizens, pleading for water. When he tried listening for his heartbeat, his "skin slipped right off". Bombs are used in war so the other side will surrender. Bombs are aimed at "enemies" as if every being is an object to destroy. So no, bombing----let alone nuclear bombing----is ethical.

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LenaWriter [7]

Answer:

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Explanation:

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2 years ago

What’s the chemical formula for lithium carbonate

nordsb [41]

Answer:

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2 years ago

Read 2 more answers

8. What is the oxidation number of N in KNO3?

Elza [17]

Answer:

The oxidation state of N in the KNO3 is +5

Explanation:

Oxidation rules:

1. Oxygen is -2, unless in peroxides.

2. Group 1 metals = +1

3. Group 2 metals = +2

4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.

5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.

So, the given formula represents the salt compound formula unit of potassium nitrate: KNO3

The formula unit is uncharged.

From our rules, we know that,

O = -2

And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.

K = +1

N = x

O = -2

Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.

+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)

x - 5 = 0

x = 5

Therefore, the oxidation number of N in KNO3 is +5.

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2 years ago

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HACTEHA [7]

Explanation:

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. ... Electric charge is carried by subatomic particles. In ordinary matter, negativecharge is carried by electrons, and positive charge is carried by the protons in the nuclei of atoms.

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3 0

2 years ago

Gastric juice is made up of substances secreted from parietal cells, chief cells, and mucous-secreting cells. The cells secrete

neonofarm [45]

Answer:

The amount of energy required to transport hydrogen ions from a cell into the stomach is 37.26KJ/mol.

Explanation:

The free change for the process can be written in terms of its equilibrium constant as:

ΔG° = $-RTInK_(eq)$

where:

R= universal gas constant

T= temperature

$K_eq$ = equilibrum constant for the process

Similarly, free energy change and cell potentia; are related to each other as follows;

ΔG= -nFE°

from above;

F = faraday's constant

n = number of electrons exchanged in the process; and

E = standard cell potential

∴ The amount of energy required for transport of hydrogen ions from a cell into stomach lumen can be calculated as:

ΔG° = $-RTInK_(eq)$

where;

[texK_eq[/tex]= $\frac{[H^+]_(cell)}{[H^+(stomach lumen)]}$

For transport of ions to an internal pH of 7.4, the transport taking place can be given as:

$H^+_{inside}$ ⇒ $H^+_{outside}$

Equilibrum constant for the transport is given as:

$K_{eq}=\frac{[H^+]_{outside}}{[H^+]_{inside}}$

$=\frac{[H^+]_{cell}}{[H^+]_{stomach lumen}}$

$[H^+]_{cell}$ = 10⁻⁷⁴

=3.98 * 10⁻⁸M

$[H^+]_{stomach lumen}$ = 10⁻²¹

=7.94 * 10⁻³M

Hence;

$K_{eq}=\frac{[H^+]_{cell}}{[H^+]_{stomachlumen}}$

= $\frac{3.98*10^{-8}}{7.94*10{-3}}$

= 5.012 × 10⁻⁶

Furthermore, free energy change for this reaction is related to the equilibrium concentration given as:

ΔG° = $-RTInK_(eq)$

If temperature T= 37° C ; in kelvin

=37° C + 273.15K

=310.15K; and

R-= 8.314 j/mol/k

substituting the values into the equation we have;

ΔG₁ = $-(8.314J/mol/K)(310.15)TIn(5.0126*10^{-6})$

= 31467.93Jmol⁻¹

≅ 31.47KJmol⁻¹

If the potential difference across the cell membrane= 60.0mV.

Energy required to cross the cell membrane will be:

ΔG₂ = $-nFE°_{membrane}$

ΔG₂ = $-(1 mol)(96.5KJ/mol/V)(60*10^{-3})$

= 5.79KJ

Therefore, for one mole of electron transfer across the membrane; the energy required is 5.79KJmol⁻¹

Now, we can calculate the total amount of energyy required to transport H⁺ ions across the membrane:

Δ $G_{total} = G_{1}+G_{2}$

= (31.47+5.79) KJmol⁻¹

= 37.26KJmol⁻¹

We can therefore conclude that;

The amount of energy required to transport ions from cell to stomach lumen is 37.26KJmol⁻¹

5 0

3 years ago