A balloon contains a fixed amount of helium. If the initial conditions are 1.12 liters, 3.00 atmospheres, and 19 degrees Celsius
, what will the final volume be when the balloon is exposed to 1.00 atmosphere pressure and 22 degrees Celsius?
1 answer:
Answer:
The final volume will be 3.39 liters
Explanation:
P1V1/T1 = P2V2/T2
P1 = 3 atm
T1 = 19( degrees celsius) + 273 = 292 K
V2 = TO BE DETERMINED
P2 =1 atm
T2 = 22( degrees celsius) + 273 = 295 k
P1V1/T1 = P2V2/T2
V2 = P1V1T2/P2T1 = (3)(1.12)(295)/(1)292) = 3.39 Liters
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