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lora16 [44]
2 years ago
11

Isaac Newton’s investigations of gravity explained which truth?

Chemistry
2 answers:
umka2103 [35]2 years ago
4 0
<span>C. Gravity acts on all objects in the universe.
think about Newtons Laws of Motion</span>
poizon [28]2 years ago
3 0
C. Gravity act on all object in the universe
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Salts usually have a low melting point
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Yes they do if that was your question
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3 years ago
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Solid carbon (C) can burn in oxygen (O2). Select
babunello [35]

Answer:

OCO

Another way of writing CO₂

Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

The reactants are carbon and oxygen. The product is carbon dioxide.

C + O₂ → CO₂

You might see the equation both ways.

C + O₂ → OCO

C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

<u>OCO is the structural way of writing CO₂.</u> Both have one carbon atom (C) and two oxygen atoms (O).

C + 2O is not possible. Oxygen, if alone, has to be at least O₂ because it's a <u>diatomic molecule</u>.

3 0
3 years ago
A 232-lb fullback runs the 40-yd dash at a speed of 19.8 ± 0.1 mi/h.
Neporo4naja [7]

Answer:

(a)  7.11 x 10⁻³⁷ m

(b)  1.11 x 10⁻³⁵ m

Explanation:

(a)  The de Broglie wavelength is given by the expression:

λ = h/p = h/mv

where h is plancks constant, p is momentum which is equal to mass times velocity.

We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.

v = 19.8 mi/h x ( 1609.34 m/s ) x ( 1 h / 3600 s ) = 8.85 m/s

m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg

λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m

(b) For this part we have to use the uncertainty principle associated with wave-matter:

ΔpΔx > = h/4π

mΔvΔx > = h/4π

Δx = h/ (4π m Δv )

Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.

Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )  

     = 0.045 m/s

Δx = h/ (4π m Δv ) = 6.626 x 10⁻³⁴ J·s / (4π x 105.33 kg x 0.045 m/s )

     = 1.11 x 10⁻³⁵ m

This calculation shows us why we should not be talking of wavelengths associatiated with everyday macroscopic objects for we are obtaining an uncertainty of 1.11 x 10⁻³⁵ m for the position of the fullback.

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