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Misha Larkins [42]
3 years ago
14

A 63.0-kg sprinter starts a race with an acceleration of 4.20 m/s2 . what is the net external force on him?

Physics
1 answer:
lora16 [44]3 years ago
8 0
From Newton's second law of motion, it was stated that the net external force on a certain object can be calculated by multiplying its mass to the acceleration. This can mathematically be expressed as,
     Fnet = m x a
where m is mass and a is acceleration.

Substitute the known values to the equation,
      Fnet = (63 kg) x (4.20 m/s²)
      Fnet = 264.6 kg m/s²
 
ANSWER: <em>Fnet = 264.6 N</em>
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Suppose a cart with no fans has a starting velocity of 2 m/s. What will be the velocity of the cart when it reaches the wall?
Roman55 [17]

Answer:

less than stating velocity due to friction and air resistance.

Explanation:

3 0
3 years ago
The ground state energy of an oscillating electron is 1.23 eV. How much energy must be added to the electron to move it to the t
Vikki [24]

Answer:

  • The energy that must be added to the electron to move it to the third excited state is  -1.153 eV
  • The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

Explanation:

Given;

Energy of electron in ground state (n = 1 ) = 1.23 eV

E₁ = 1.23 eV

Eₙ = E₁ /n²

where;

E₁ is the energy of the electron in ground state

n is the energy level,

For third excited state, n = 4

E₄ = E₁ /4²

E₄ = (1.23 eV) / 16

E₄ = 0.077 eV

Change in energy level, = E₄ - E₁ = 0.077 eV - 1.23 eV = -1.153 eV

The energy that must be added to the electron to move it to the third excited state is  -1.153 eV

For fourth excited state, n = 5

E₅ = E₁ /5²

E₄ = (1.23 eV) / 25

E₄ = 0.049 eV

Change in energy level, = E₅ - E₁ = 0.049 eV - 1.23 eV = -1.181 eV

The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

5 0
3 years ago
The speed at which an object falls and the acceleration at which it falls are
allochka39001 [22]

No, the speed at which an object falls is not equal to the acceleration at which it falls.

Answer:

Option B

Explanation:

Speed is defined as how fast an object can cover a specific distance and in what time it covers. So it is measured as the ratio of distance covered to the time taken to cover that distance. While acceleration is the rate of change of velocity. Moreover, speed is a scalar quantity and acceleration is a vector quantity. So most of the times, the direction will play an important role in the varying values of speed and acceleration. Also, acceleration of an object will depend upon the force and mass of the object. Thus, speed and acceleration will not attain same value always.

6 0
3 years ago
Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at
Maurinko [17]

Answer:

v=0.3381\ m.s^{-1} in the direction of motion of Jacob

Explanation:

Given:

mass  of Jacob, m_j=45\ kg

velocity of Jacob, v_j=8.08\ m.s^{-1}

mass of Ethan, m_e=31\ kg

velocity of Ethan, v_e=10.9\ m.s^{-1}

Now using the conservation of linear momentum for the case:

(When the two masses in motion combine to form one after the collision then they will move together in the direction of the greater momentum.)

(m_j+m_e).v=m_j.v_j-m_e.v_e

(45+31)\times v=45\times 8.08-31\times 10.9

v=0.3381\ m.s^{-1} in the direction of motion of Jacob as it was assumed to be positive.

5 0
3 years ago
Solve for M₂
soldi70 [24.7K]

Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

5 0
3 years ago
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