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2 years ago

Help me solve this please?

Physics

2 answers:

Ray Of Light [21]2 years ago

7 0

the force is given by the equation

q*v*B [email protected]

thus it will be

(1.6*10^-19)*(7.8*10^4)*(3)*1/√2 which gives 2.6*10^-14 N

Lunna [17]2 years ago

4 0

Formula

F = q*v*B Sin (theta)

Givens

q = 1.6*10^-19 coulombs

v = 7.8*10^4 m/s

B = 3 Tesla

phi = 45 degrees.

Solution

F = q*v*B * sin(45)

F = 1.6*10^-19 * 7.8*10^4 * 3 * Sin(45)

F = 2.6 * 10 ^-14

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Both form when warm air rises:)

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3 years ago

Read 2 more answers

4. How long will it take a car travelling with a speed of 160 km hr to cover a distance of 700 meters? Hint: km/hr should be con

Inessa [10]

Answer:

15.8 seconds

Explanation:

Create an extended calculation to convert all the unit to what you need.

160 km 1000 m 1 hour 1 min

----------- x ------------- x -------------- x ---------- = 44.4 m/s

1 hour 1 km 60 min 60 sec

So 160km/hr is equal to 44.4m/s

Now you can figure out how many seconds it will take to go 700 meters.

44.4 m

---------- X x sec = 700 m

1 sec

Solve for x sec

x sec = 700m / 44.4 m/s

= 15.8 seconds

3 0

2 years ago

Consider a situation of simple harmonic motion in which the distance between the endpoints is 2.39 m and exactly 8 cycles are co

aivan3 [116]

Answer:

1.195 m

2.8375 s

2.21433 rad/s

Explanation:

d = Distance = 2.39 m

N = Number of cycles = 8

t = Time to complete 8 cycles = 22.7 s

Radius would be equal to the distance divided by 2

$r=\frac{d}{2}\\\Rightarrow r=\frac{2.39}{2}\\\Rightarrow r=1.195\ m$

The radius is 1.195 m

Time period would be given by

$T=\frac{t}{N}\\\Rightarrow T=\frac{22.7}{8}\\\Rightarrow T=2.8375\ s$

Time period of the motion is 2.8375 s

Angular speed is given by

$\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{2.8375}\\\Rightarrow \omega=2.21433\ rad/s$

The angular speed of the motion is 2.21433 rad/s

4 0

3 years ago

A World War II bomber flies horizontally over level terrain, with a speed of 287 m/s relative to the ground and at an altitude o

Scorpion4ik [409]

Answer: 7.38 km

Explanation: The attachment shows the illustration diagram for the question.

The range of the bomb's motion as obtained from the equations of motion,

H = u(y) t + 0.5g(t^2)

U(y) = initial vertical component of velocity = 0 m/s

That means t = √(2H/g)

The horizontal distance covered, R,

R = u(x) t = u(x) √(2H/g)

Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2

R = 287 √(2×3240/9.8) = 7380 m = 7.38 km

6 0

2 years ago

If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the

Ede4ka [16]

The change in the internal energy of the system is 110 kJ.

<h3>What is internal energy?</h3>

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

ΔU = Q-W.................... Equation 1

Where:

ΔU = Change in internal energy
Q = Heat absorbed from the surroundings
W = work done by the system

From the question,

Given:

Q = 115 kJ

W = 45. 0 kJ

Substitute these values into equation 1

ΔU = 155-45

ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

Learn more about change in internal energy here: brainly.com/question/4654659

4 0

2 years ago