The statement that describes how work and power are similar is D. you must know time and energy to calculate both.
I am not completely sure though, so I hope this helps. :)
The given question is incomplete. The complete question is as follows.
In a nuclear physics experiment, a proton (mass
kg, charge +e =
C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed
m/s. The proton comes momentarily to rest at a distance
m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are
m apart?
Explanation:
The given data is as follows.
Mass of proton =
kg
Charge of proton = 
Speed of proton = 
Distance traveled = 
We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.
=

where, 
U = 
Putting the given values into the above formula as follows.
U = 
= 
= 
Therefore, we can conclude that the electric potential energy of the proton and nucleus is
.
Answer:
Gravitational pull
Explanation:
There are four fundamental forces in nature:
- Gravitational force: it is an attractive force exerted between all objects having mass. Its magnitude is proportional to the product of the masses and inversely proportional to the square of the distance between the objects.
- Electromagnetic force: it is the force exerted between electrically charged object. It can be either attractive ore repulsive. Its magnitude is proportional to the product of the charges and inversely proportional to the square of the distance between the objects.
- Strong nuclear force: it is the force responsible for holding protons and neutrons together in the nuclei of the atoms. It is attractive and acts only on a very short scale.
- Weak nuclear force: it is the force responsible for certain nuclear decay processes (radioactivity).
In this problem, landslides occur when certain masses of terrain are attracted towards the ground - they are attracted because of the gravitational force.
So, the correct answer is
gravitational pull
Answer
m/s rate of change of dispalcement per sec. ie velocity
m/s^2 is (m/s)/s ie rate of change of velocity per sec. ie accelerationplanation:
Thermal energy is the force of the kinetic and potential energies of all particles in an object