A friend tells you he read on a web site that earth is getting smaller, What can you tell him that shows Earth's size is not cha
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Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Explanation :
The given half reaction are :
1st half reaction :
The reduction potential of this reaction = +0.80 V
2nd half reaction :
The reduction potential of this reaction = -0.74 V
From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.
Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.
The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.
Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Answer: The empirical formula for the given compound is and molecular formula for the given compound is
Explanation : Given,
Mass of C = 18.24 g
Mass of H = 0.51 g
Mass of F = 16.91 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Fluorine =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.51 moles.
For Carbon =
For Hydrogen =
For Fluorine =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : F = 3 : 1 : 2
The empirical formula for the given compound is
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
We are given:
Molar mass = 562.0 g/mol
Mass of empirical formula = 3(12) + 1(1) + 2(19) = 75 g/eq
Putting values in above equation, we get:
Multiplying this valency by the subscript of every element of empirical formula, we get:
Thus, the molecular formula for the given compound is