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2 years ago

Which mineral is used in batteries

1 answer:

4 0

Batteries come in all shapes and sizes, and depending on the type of battery, the minerals that compose them are mainly lithium, cobalt, graphite, nickel and manganese.

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Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.

olasank [31]

Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)$

The solvent volume will be:

1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

Then the mass of the solvent is:

m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{m_1}{M_1*m_2}$

$\omega = \dfrac{200}{132*0,821}$

$\omega = \dfrac{200}{108,372}$

$\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

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Another way to find the answer:

We have the following data:

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

Let's find the number of mols (n), let's see:

 $n = \dfrac{m_1}{M_1}$

$n = \dfrac{200}{132}$

$n \approx 1,5\:mol$

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{n}{m_2}$

$\omega = \dfrac{1,5}{0,8}$

$
\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

I hope this helps. =)

7 0

2 years ago

Sodium hydroxide + nitric acid → in double replacement

Kaylis [27]

The answer is sodium hydroxide

3 0

1 year ago

Maya, a student, performs a titration. She completes the following steps as part of her titration procedure. 1. She cleans and r

Salsk061 [2.6K]

Answer is: No, because she did not stop adding base once the color changed.
The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop or results are going to be wrong, because the equivalence point of titration is not measured right.

6 0

3 years ago

Is this correct pls answer as soon as possible

Lunna [17]

Answer: Yes

Explanation:

I just know it is.

4 0

2 years ago

The energy pyramid below shows a possible

ExtremeBDS [4]

Energy transfer is not an efficient process.

Explanation:

There is less amount of energy in the top of the energy pyramid than at the bottom because energy transfer is not an efficient process. During the process of energy transferring, some amount is lost and some are converted to other forms of energy.

The sun is the ultimate source of energy for all life in the solar system.
When autotrophs takes this energy, they produce food from it.
They use light energy from the sun to produce chemical energy in food.
Even this conversion process waste precious amount of energy.
As one goes up the pyramid, more energy is lost during the process of converting from one form to another.

Learn more:

laws of thermodynamics brainly.com/question/11769517

#learnwithBrainly

7 0

2 years ago

Read 2 more answers