All categories

3 years ago

Which mineral is used in batteries

1 answer:

4 0

Batteries come in all shapes and sizes, and depending on the type of battery, the minerals that compose them are mainly lithium, cobalt, graphite, nickel and manganese.

You might be interested in

calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is $-22Jmole^-^1k^-^1$

(b) The normal boiling point of water (J·K−1·mol−1) is $-109Jmole^-^1K^-^1$

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole

Explanation:

Lets calculate

(a) - General equation -

$(\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p$ = $-5_m(\beta )+5_m(\alpha )$ = $-\frac{\Delta H}{T}$

$\alpha ,\beta$ → phases

ΔH → enthalpy of transition

T → temperature transition

$(\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p$ = $= -\frac{\Delta_fH}{T_f}$

= $\frac{-6.008kJ/mole}{273.15K}$ ( $\Delta_fH$ is the enthalpy of fusion of water)

= $-22Jmole^-^1k^-^1$

(b) $(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}$

= $\frac{40.656kJ/mole}{373.15K}$ ( $\Delta_v_a_p_o_u_rH$ is the enthalpy of vaporization)

= $-109Jmole^-^1K^-^1$

$[\mu(l-5$ ° $C)-\mu(l,0$ ° $C)]$ = $[\mu(s-5$ ° $C)-\mu(s,0$ ° $C)]$ $=-S_m$ ΔT

$\mu(l,-5$ ° $C)-\mu(s,-5$ ° $C)=-Sm\DeltaT [\mu(l,0$

$\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)$

= 109J/mole

6 0

2 years ago

How many moles of Na are needed to produce moles of NaCl in the reaction below

MArishka [77]

I think it’s 1 mole
If Iam not mistaken

3 0

3 years ago

It takes much less energy to change the temperature of oil than it does to change the temperature of water

Andrew [12]

Answer:

i think so

Explanation:

8 0

3 years ago

7. Calculate the amount of energy required heat 100.g to <br> H2O(s) changes to H2O(l) at 0°C

Brrunno [24]

Answer:

33300J

Explanation:

Given parameters:

Mass of ice = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

So;

H = mL

m is the mass

L is the latent heat of melting ice

Now, insert the parameters and solve;

H = mL

mass from gram to kilogram;

100g gives 0.1kg

H = 0.1 x 3.33 x 10⁵ = 33300J

8 0

3 years ago

Describe the three subatomic particles (protons, neutrons, and electrons) in terms of their mass, charge, and location within th

atroni [7]

Particle mass charge      location

protons    1.673*10 ^ - 27 kg 1.6*10 ^ -19 C in the nucleus
neutrons   1.675*10 ^ - 27 kg 0    in the nucleus
electron    9.11 * 10 ^ - 31 kg    -1.6 * 10 ^ - 19 C    around the nucleus (orbitals)

Protons and neutrons have almost same masses. Mass of electrons is 1/1840 the mass of the protons.

Protons and electrons have the same magnitud of charge with different sign. Protons are positive and electrons are negative. Neutrons do not have charge.

3 0

3 years ago