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Shalnov [3]
3 years ago
14

1. By means of orbital diagrams, write down the

Chemistry
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

a) 1s22s22p63s1

b) 3s² 3p¹

c) 1s22s22p63s23p3

d) 3s² 3p⁵

e) 3s2

f) 1s22s22p63s23p2

g) 1s22s22p63s23p4

h) 3s² 3p⁶

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Y_Kistochka [10]

Answer:

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3 years ago
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Which of the following is the ground state of an atom? Which is its excited state? Which is an impossible electron configuration
Rus_ich [418]

For this specific problem, these would be the answer to the following choices:

a. excited

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c. impossible

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A type of plate boundary that is transform faults (easily seen where they cut at right angles to the mid-ocean ridges) A.) conve
34kurt
The answer is Option C (Divergent Plate Boundary)

Mapping efforts have shown that mid-ocean ridges<span> are discontinuous structures that cut at </span>right angles<span> to its length at various transform faults. They typically </span><span>demarcate the </span>boundary <span>between two tectonic plates, and are therefore called </span>divergent<span> plate </span>boundaries.
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Which statement is best described as a atom
myrzilka [38]

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A graduated cylinder contains 20.8 mL of water. What is the new water level, in milliliters, after 35.2 g of silver metal is sub
stepladder [879]

<u>Answer:</u> The new water level of the cylinder is 24.16 mL

<u>Explanation:</u>

To calculate the volume of water displaced by silver, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of silver = 10.49 g/mL

Mass of silver = 35.2 g

Putting values in above equation, we get:

10.49g/mL=\frac{35.2g}{\text{Volume of silver}}\\\\\text{Volume of silver}=\frac{35.2g}{10.49g/mL}=3.36mL

We are given:

Volume of graduated cylinder = 20.8 mL

New water level of the cylinder = Volume of graduated cylinder + Volume of water displaced by silver

New water level of the cylinder = (20.8 + 3.36) mL = 24.16 mL

Hence, the new water level of the cylinder is 24.16 mL

5 0
3 years ago
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