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viva [34]
3 years ago
9

Solve picture question. Mathematics.

Mathematics
2 answers:
irinina [24]3 years ago
8 0
Cross multiplication!
\frac{7}{8} = \frac{x}{24}
7 × 24 = 8x
168 = 8x

Divide both sides by 8 to isolate x

\frac{168}{8} = \frac{8x}{8}
8 and 8 cancels out

21 = x
bagirrra123 [75]3 years ago
4 0
8*?=24? 8*3=24. So multiply 7 also by 3, and the answer is 21 :)
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At which value in the domain does f(x)=0 ?
lina2011 [118]

f(x)=0

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At x intercepts y is always 0

so we find all the x intercepts.

x intercepts are the points where the graph crosses x axis

In the graph we can see that the graph crosses x axis at

-2.5 , -0.75 and 1

-2.5 , -0.75 and 1 are the domain where f(x)=0

5 0
3 years ago
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One dozen bananas weigh 3 pounds, how much do 2 bananas weigh?
pantera1 [17]

Answer: 50

Step-by-step explanation: If a dozen is 3 pounds then half a dozen would 6 which should be 1.50 lb. Now we need to know how much 1 banana weights. lets add all twelve until we have 3 pounds. 12 x 25 = 300 or 3.00 lb so we now know 2 bananas weight 50.

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3 years ago
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Step-by-step explanation:

8 0
2 years ago
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The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
defon
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
           h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

 sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
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7 0
2 years ago
Find the value of the variable that results in congruent triangles for numbers 6 and 8.
mariarad [96]

Answer:

x = 28

Step-by-step explanation:

From the figure attached,

AC ≅ FH [Given]

BC ≅ GH [Given]

AB ≅ FG [Given]

ΔABC ≅ ΔFGH [By SSS property of congruence]

Since, m∠A + m∠B + m∠C = 180°

50° + 69° + m∠C = 180°

119° + m∠C = 180°

m∠C = 180° - 119°

m∠C = 61°

m∠C = m∠H [Since, ΔABC ≅ ΔFGH]

(2x + 5)° = 61°

2x = 61 - 5

2x = 56

x = 28

8 0
2 years ago
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