Question 12 of 32

When 2.5 g of blue copper(ii) sulfate crystals were heated, 1.6 g of a white solid were left in tube A

Zinaida [17]

Answer:

b po answerpa brainlest

8 0

3 years ago

Consider the following hypothetical aqueous reaction. A flask is charged with .065 mol of A in a total volume of 100.0 mL. The f

Inga [223]

Answer: 0.422 M⁻¹s⁻¹

Explanation: Reaction Rate is the speed of decomposition of the reactant(s) per unit of time.

A Rate Law relates concentration of reactants, rate reaction and rate constant:

$r=k[A]^{x}[B]^{y}$

where

[A] and [B] are reactants concentration

x and y are reaction order, not related to the stoichiometric coefficients

k is rate constant

r is rate

Before calculating rate constant, first we have to determine reaction order.

In this question, the reactio order is 2. So, the rate law for it is

$-\frac{d[A]}{dt} =k[A]^{2}$

and the integrated formula is

$\frac{1}{[A]} =\frac{1}{[A]_{0}} +kt$

in which

[A]₀ is initial concentration of reactant

Then, using initial concentration at initial time and final concentration at final time:

$\frac{1}{0.031} =\frac{1}{0.065} +k(40)$

$40k=\frac{1}{0.031}-\frac{1}{0.065}$

$40k=32.26-15.38$

k = 0.422

The rate constant for the reaction is 0.422 M⁻¹.s⁻¹

3 0

3 years ago

A solution is made by adding 200 g table salt to 1

pochemuha

We say that the solution is unsaturated.

Explanation:

If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.

Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.

We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.

Learn more about:

solubility

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7 0

3 years ago

Read 2 more answers

Mengapakah gelung pemanas di dalam cerek elektrik berada di dasar cerek?

shepuryov [24]

English, please. Does this have something to do with an electrical barometer

5 0

3 years ago

PJ’s unknown solid 1) dissolves in hot ethanol, 2) is essentially insoluble in hexane, and 3) is insoluble in cold water, but sp

Gnoma [55]

Answer:

1. The solid is dissolved in the hot solvent (ethanol or water);

2. If the impurities are not dissolved, they are separated by filtration;

3. The solution is then cold, and the crystals of the solid are formed;

4. The solution is filtrated and the pure solid is obtained.

Explanation:

The recrystallization is a process to separate impurities from a solid. The solid with the impurities is dissolved in a hot solvent, and, is insoluble in the cold one. But the impurities must be soluble in the cold solvent, or insoluble in the hot one.

If the impurities are soluble in the cold solvent, then, the crystals of the analyte will be removed, and if they are insoluble in the hot solvent, then its crystal is removed first.

So let's assume that the solid is insoluble in hot ethanol, and soluble in hot water. Because its insoluble in hexane, the recrystallization is not possible with it. So the procedure would be:

1. The solid is dissolved in the hot solvent (ethanol or water);

2. If the impurities are not dissolved, they are separated by filtration;

3. The solution is then cold, and the crystals of the solid are formed;

4. The solution is filtrated and the pure solid is obtained.

5 0

3 years ago