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MariettaO [177]
3 years ago
12

What is the electron configuration for Sodium (Na)?

Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0
The electron configuration for Sodium (Na) is [Ne] 3s1
Airida [17]3 years ago
5 0
Sodium is the 11th element in the periodic table so it will have 11 electrons (if you're not sure if something is right always check how many electrons they're are it's like checking your work in math). There are 4 energy "types" in the periodic table: S,P,D and F. Starting from the top left you are in the first energy level 1 (in the S area which is always the first two elements on the left of the table before the transition metals) and there are two elements (hydrogen and helium) so you have 1s^2 then you go down to the second column and you have the first two elements which are Lithium and Beryllium so your next config is 2s^2. Now you have more elements on the left and those are in the "P energy section" and there are 6 elements there so you put 2p^6. Now you move down again and you're in the 3rd energy level and sodium is the 1st element and so you only need to put 3s^1. Your econfig is 1s^2 2s^2 2p^6 and 3s^1
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How to change 5 % W/V of NaCl to ppm , M ? molar mass = 58.5<br>please clear explain​
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Answer:

50000ppm and 0.855M.

Explanation:

ppm is an unit of chemistry defined as the ratio between mg of solute (NaCl) and Liters of solution. Molarity, M, is the ratio between moles of NaCl and liters

A 5% (w/v) NaCl contains 5g of NaCl in 100mL of solution.

To solve the ppm of this solution we need to find the mg of NaCl and the L of solution:

<em>mg NaCl:</em>

5g * (1000mg / 1g) = 5000mg

<em>L Solution:</em>

100mL * (1L / 1000mL) = 0.100L

ppm:

5000mg / 0.100L = 50000ppm

To find molarity we need to obtain the moles of NaCl in 5g using its molar mass:

5g * (1mol / 58.5g) = 0.0855moles NaCl

Molarity:

0.0855mol NaCl / 0.100L = 0.855M

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