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ANTONII [103]
3 years ago
6

Creatine phosphate

Chemistry
1 answer:
Over [174]3 years ago
8 0

Answer: C. Acts as energy reserve in muscle tissue.

Explanation:

Creatine Phosphate is a high energy compound that can be found in muscle tissue.

It serves as an extra energy storage, since the normal metabolism cannot supply the high energy requirement of a muscle at work.

Creatine Phosphate is quickly transfered to ADP, for the production of ATP needed for muscle contraction.

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5C + 6O2 = ? What will be the product of molecules formed from this equation?
harina [27]

Answer:5 moles ofCarbonmonoxide and 3.5 moles of oxygen gas.This in combine to yield carbon dioxide.

Explanation:

5C + 6O2----------5CO + 7/2O2.

When carbon combine with oxygen, carbon monoxide is formed first and it later recombine with oxygen to yield carbon dioxide.

6 0
3 years ago
Read 2 more answers
please help 13 points!!! cell wall chloroplasts mitochondria small vacuoles eukaryote cells How would you change the characteris
Angelina_Jolie [31]

Answer:

A.

Explanation:

It’s just right

4 0
2 years ago
Calculate the number of moles of each compound, given the number of molecules.
brilliants [131]

Answer:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

Explanation:

1.  2.46\times 10^{21} molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

5 0
2 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
Read 2 more answers
Which bond has the greatest ionic character? A) H-Cl B) H-F c) H-O d) H-N
Len [333]
 I really hope that this helps.  H-F because the difference in electronegativity is the greatest, about 1.9 on the Pauling scale. The term means which bond has the greatest polarity and is thus most similar to an ionic bond, which involves the transfer of an electron (in opposition to covalent bonds, which share electrons). It is H-F because out of all the atoms here bonded with H, ie hydrogen, F is the most electronegative which means it can pull the bonded electrons to itself more than can Cl, O, and N. <span>That means a stronger polarization of the electron cloud forming the bond with hydrogen and therefore a stronger ionic character.</span>
5 0
3 years ago
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