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2 years ago

What mass of solid lead would displace exactly 234.6 liters of water?

2 answers:

6 0

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The mass of solid lead would displace exactly 234.6 liters of water should be 2,674,440

BARSIC [14]2 years ago

3 0

The answer is 2660.6 kg

Exactly 234.6 liters of water is displaced by lead hence giving us the volume of the metal, according to Archimedes' principle of displacement.

Lead has a density of 11341 kg/m3 and we know that 1000L = 1m3. Therefore;

234.6 liters = 0.2346m3

0.2346 * 11341

= 2660.6 kg

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3 years ago

What is the molarity of a solution in which 58g of nacl are dissolved in 1.0 l of solution

Lady_Fox [76]

Hey there :

Molar mass of NaCl = 58.44 g/mol

Number of moles :

n = mass of solute / molar mass

n = 58 / 58.44

n = 0.9924 moles of NaCl

Volume = 1.0 L

Therefore:

Molarity = number of moles / volume ( L )

Molarity = 0.9924 / 1.0

Molarity = 0.9924 M

Hope that helps!

7 0

3 years ago

The total volume of seawater is 1.5 x 1021L .Assume that seawater contains 3.1 percent sodium chloride by mass and that its dens

son4ous [18]

Answer:

Mass in kg = 4.7*10^19 kg

Mass in tons = 5.2*10^16 tons

Explanation:

Given:

Total volume of sea water = 1.5*10^21 L

Mass % NaCl in seawater = 3.1%

Density of seawater = 1.03 g/ml

To determine:

Total mass of NaCl in kg and in tons

Calculation:

Unit conversion:

1 L = 1000 ml

The volume of seawater in ml is:

$=\frac{1.5*10^{21}L*1000ml }{1L} =1.5*10^{24} ml$

$Mass\ seawater = Density*volume = 1.03g/ml*1.5*10^{24} ml=1.5*10^{24}g$

$Mass\ NaCl\ in\ seawater = \frac{3.1}{100}*1.5*10^{24} g=4.7*10^{22} g$

To convert mass from g to Kg:

1000 g = 1 kg

$Mass\ seawater(kg) = \frac{4.7*10^{22}g*1kg }{1000g} =4.7*10^{19} kg$

To convert mass from g to tons:

1 ton = 9.072*10^6 g

$Mass\ seawater(tons) = \frac{4.7*10^{22}g*1ton }{9.072*10^{6}g } =5.2*10^{16} tons$

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3 years ago

How did the industrial revolution contribute to global climate change

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Explanation:

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2 years ago

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = $5.61*10^-^5$

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3 years ago