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forsale [732]
3 years ago
7

HELP ASAP PLZ!!!

Chemistry
2 answers:
Pepsi [2]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

Since, the chemical formula of acetic acid is CH_{3}COOH. And, symbol which represents a carbon atom is C, hydrogen atom is represented by H and an oxygen atom is represented by O.

Therefore, as in a molecule of acetic acid there are total 2 carbon atoms, 4 hydrogen atoms and total 2 oxygen atoms.

Thus, we can conclude that there are 2 atoms of the element carbon (C) are in a molecule of acetic acid.

LuckyWell [14K]3 years ago
5 0

Answer:

2

Explanation:

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The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

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Now we have to calculate the Gibbs free energy.

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\Delta G^o=-nFE^o

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F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

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