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RideAnS [48]
3 years ago
15

Treatment of butanedioic (succinic) anhydride with ammonia at elevated temperature leads to a compound of molecular formula C4H5

NO2. What is the structure of this product? [Hint: You need to think about the reactivity not only of acid anhydrides but also of amides and carboxylic acids]

Chemistry
1 answer:
artcher [175]3 years ago
5 0

Answer:

The product is Methyl cyanoacetate

Explanation: see structure attached

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A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of
Rus_ich [418]
<span> 52.0ml of 0.35M CH3COOH : 0.052 L(0.35M) = .0182 mol of CH3COOH. 
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<span>31.0ml of 0.40M NaOH : .031 L(0.40M) = .0124 mol of NaOH. 
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<span>After the  reaction, .0124 Mol CH3COO- is generated and .058 mol CH3COOH is left un-reacted. The concentration would be 12.4/V and 5.8/V, respectively. Therefore:

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<span>pH = -log([H+]) = -log(Ka*[CH3COOH]/[CH3COO-]) </span>
<span>= -log(1.8x10^-5*5.8/12.4) = 5.07</span>
6 0
3 years ago
Sodium oxide reacts with water to make sodium hydroxide.
Vlada [557]

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So the total mass is 50 plus 150 grams the heat capacity 4.18 joules per gram per degree C. And the temperature change is 36 minus 25 and so we can calculate Delta H for the reaction that takes place.

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By titration, it is found that 28.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the
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*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

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