The atomic particles responsible for forming bonds with other atoms are

1 answer:

7 0

The most famous types of bonds are the ionic bonds and the covalent bonds.
The ionic bond is formed due to the transfer of electrons from one atom to another. While the covalent bond is formed due to sharing of electrons between atoms where each atom contributes with one or more electron to be shared.

Based on this, we can deduce that electrons are the atomic particles that are responsible for the formation of bonds with other atoms.

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Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c

nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart + H₂O ⇄ H₃O⁺ + HTart⁻ Ka1

HTart⁻ + H₂O ⇄ H₃O⁺ + Tart⁻² Ka2

When we anaylse the base, we have

Tart⁻² + H₂O ⇄ OH⁻ + HTart⁻ Kb1

HTart⁻ + H₂O ⇄ OH⁻ + H₂Tart Kb2

Remember that Ka1 . Kb2 = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1 → 1×10⁻¹⁴ / 9.20×10⁻⁴ = 1.08×10⁻¹¹

so pKb = - log Kb2 → - log 1.08×10⁻¹¹ = 10.96

7 0

3 years ago

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Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which t

finlep [7]

Answer:

The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.

Explanation

lets calculate -

Rydberg equation- $\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})$

where , $\pi$ is wavelength , R is Rydberg constant ( $1.097\times10^7$ ), $n_1$ and $n_2$ are the quantum numbers of the energy levels. (where $n_1=2 , n_2=4$ )