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kari74 [83]
3 years ago
15

Nitric acid (HNO3) is used in the production of fertilizer, dyes, drugs, and explosives. Calculate the pH of a HNO3 solution hav

ing a hydrogen ion concentration of 0.71 M.
Chemistry
2 answers:
Sindrei [870]3 years ago
5 0

Answer:

0.15

Explanation:

Whenever we are asked to calculate the pH of a particular solution in Chemistry it means that we are to look for its degree of acidity or basicity of such solution. Since the question is about an acidic solution, that is HNO3 we are to find the degree of acidity in the solution.

Therefore, the formula for the pH of a solution is given below;

pH = - log [ H^+].

In the question, we are given the hydrogen ion concentration to be = 0.71 M.

Hence, pH = - log [0.71].

pH = 0.14874165128092471.

pH =0.15.

It means that the solution is very acidic.

Alona [7]3 years ago
3 0

Answer:

pH of HNO₃ having an hydrogen ion concentration of 0.71M is 0.149

Explanation:

HNO₃ (aqueous) ⇄ H⁺ + NO3⁻

The pH is defined as the negative log of the hydrogen ion concentration

pH = - log [H⁺]

From the question, the hydrogen ion concentration is given as 0.71M, therefore

pH = -log [0.71]

     = 0.149

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The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

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3 years ago
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