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2 years ago

Which action could cause a sample of liquid to boil?

Chemistry

2 answers:

bija089 [108]2 years ago

8 0

B I’m pretty sure this is right

bearhunter [10]2 years ago

4 0

Answer:

b i think.

Explanation:

good luck sorry if it is not correct

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A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

(a) the temperature on a warm summer day is 87 Â°f. what is the temperature in Â°c? (b) many scientific data are reported at 25

olchik [2.2K]

Answers:

(a) 30.55 °C

(b) 298 K and 77°F

(c) 204.44 °C and 477.44 K

(d) -320.8 °F and -196 °C

Explanation:

Converting °C into °F;

°F = °C × 1.8 + 32

Converting °F into °C;

°C = °F - 32 ÷ 1,8

Converting °C into K;

K = °C + 273

Converting K into °C;

°C = K - 273

8 0

3 years ago

The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume

Viktor [21]

Answer:

0.83 mL

Explanation:

Given data

Initial concentration (C₁): 12 M

Initial volume (V₁): ?

Final concentration (C₂): 1.0 M

Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0

3 years ago

Which element would most likely have a positive electron affinity

STatiana [176]

Answer : Electron affinity (Eea) of an atom or molecule can be defined as the amount of energy released or spent when an electron is being added to a neutral atom or molecule in the gaseous state to form a negative ion.

Chlorine is considered to be the element which has highest electron affinity in the modern periodic table.

The general formula is X + $e^{-}$ ----> $X^{-}$ + energy

It is found that nonmetals have more positive Eea than metals.

Electron affinity increases across the group from left to right in the modern periodic table. Elements with small nucleus have high electron affinity.

7 0

2 years ago

What organic product would be formed from the reaction of 1-bromo-2-methylpropane (isobutyl bromide), (ch3)2chch2br, with mg, et

miskamm [114]

The reaction of 1-bromo-2-methylpropane (isobutyl bromide), $(CH_3)_2CHCH_2Br$ , with $Mg$ , and $Et_2O$ results in the formation of an adduct of formula $(CH_3)_2CHCH_2MgBr$ known as grignard reagent, an organometallic reagent, which on reacting with $H_3O^{+}$ results in the formation of isobutane.

The reaction is shown in the image.

4 0

3 years ago