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3 years ago

14

What is the difference between stretching a t shirt and stretching a rubber band?

1 answer:

labwork [276]3 years ago

4 0

It depends on their tension. Normally, the rubber band store more tension than a t shirt.

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Explain how potential difference produces a current in a conductor.

Yuki888 [10]

Potential difference is the work done In moving a charge from one point to another in a conductor

5 0

4 years ago

Ngle of a block is 45 degrees. What is the refractive index

lyudmila [28]

1.6 ??? I hope I’m right

3 0

3 years ago

A circular plate of 500-mm diameter is maintained at T1 = 600 K and is positioned coaxial to a conical shape. The back side of t

drek231 [11]

For part a)
Since the conical surface is not exposed to the radiation coming from the walls only from the circular plate and assuming steady state, the temperature of the conical surface is also equal to the temperature of the circular plate. T2 = 600 K

For part b)
To maintain the temperature of the circular plate, the power required would be calculated using:
Q = Aσ(T₁⁴ - Tw⁴)
Q = π(500x10^-3)²/4 (5.67x10^-8)(600⁴ - 300⁴)
Q = 5410.65 W

5 0

3 years ago

If the coefficient of static friction is 0.357, and the same ladder makes a 58.0° angle with respect to the horizontal, how far

zavuch27 [327]

Answer: d= 0.57* l

Explanation:

We need to check that before ladder slips the length of ladder the painter can climb.

So we need to satisfy the equilibrium conditions.

So for ∑Fx=0, ∑Fy=0 and ∑M=0

We have,

At the base of ladder, two components N₁ acting vertical and f₁ acting horizontal

At the top of ladder, N₂ acting horizontal

And Between somewhere we have the weight of painter acting downward equal to= mg

So, we have N₁=mg

and also mg*d*cosФ= N₂*l*sin∅

So,

d= $\frac{N2}{mg}*l$ * tan∅

Also, we have f₁=N₂

As f₁= чN₁

So f₁= 0.357 * 69.1 * 9.8

f₁= 241.75

Putting in d equation, we have

d= $\frac{241.75}{69.1*9.8} *l$ * tan 58

d= 0.57* l

So painter can be along the 57% of length before the ladder begins to slip

3 0

3 years ago

Read 2 more answers

A bike travels at a constant speed for 4.00 m/s for 5.00 seconds. How far does it go

kicyunya [14]

Answer:

20 metres

Explanation:

<em>Speed</em><em> </em><em>=</em><em> </em><em>distance</em><em> </em><em>÷</em><em> </em><em>time</em>

<em> </em>

<em> $s = \frac{d}{t}$ </em>

If we substitute the values:

$4 = \frac{d}{5}$

<em> $20 = d$ </em>

3 0

3 years ago

Read 2 more answers