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stepladder [879]
3 years ago
8

A rope exerts a 35N force on an object at an angle of 12N degrees above the horizontal. What horizontal and vertical components

of the force?
Physics
1 answer:
nekit [7.7K]3 years ago
5 0

Answer:

The horizontal component of the force, F_x= 34.24 \ N

The  vertical component of the force, F_y=7.28 \ N

Explanation:

Given;

Force on the rope, F = 35 N

angle between the rope and the horizontal = 12 °

The horizontal component of the force is given by;

F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N

The vertical component of the force is given by;

F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N

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Answer:

d. None of the above.

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In the complete trajectory the gravitational acceleration is always present. Then, the grasshopper's acceleration vector is not zero.

At the top of the arc the grasshopper is not at equilibrium because the gravitational force is constantly acting on the grasshopper.

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First we have to calculate the wavelength of hydrogen atom.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

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n_i= Lower energy level = 2

Putting the values, in above equation, we get:

\frac{1}{\lambda}=(10973731.6)\left(\frac{1}{2^2}-\frac{1}{3^2} \right )

\lambda=6.56\times 10^{-7}m

Now we have to calculate the energy.

E=\frac{hc}{\lambda}

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c = speed of light = 3\times 10^8m/s

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Putting the values, in this formula, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{6.56\times 10^{-7}m}

E=3.03\times 10^{-19}J

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Answer:

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