Question

A rope exerts a 35N force on an object at an angle of 12N degrees above the horizontal. What horizontal and vertical components of the force?

Answer 1

Answer:

The horizontal component of the force, $F_x= 34.24 \ N$

The  vertical component of the force, $F_y=7.28 \ N$

Explanation:

Given;

Force on the rope, F = 35 N

angle between the rope and the horizontal = 12 °

The horizontal component of the force is given by;

$F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N$

The vertical component of the force is given by;

$F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N$