1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stepladder [879]
2 years ago
8

A rope exerts a 35N force on an object at an angle of 12N degrees above the horizontal. What horizontal and vertical components

of the force?
Physics
1 answer:
nekit [7.7K]2 years ago
5 0

Answer:

The horizontal component of the force, F_x= 34.24 \ N

The  vertical component of the force, F_y=7.28 \ N

Explanation:

Given;

Force on the rope, F = 35 N

angle between the rope and the horizontal = 12 °

The horizontal component of the force is given by;

F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N

The vertical component of the force is given by;

F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N

You might be interested in
As a wave travels through a medium, it displaces particles in a direction parallel to the motion of the wave. We can conclude th
Gre4nikov [31]
Transvere wave because the direction which the particles are being displaced
5 0
3 years ago
What is one positive outcome of the recent<br>events?​
fenix001 [56]

Answer:

Analyze the positive and negative consequences of catastrophic events of the last 40-50 years and the individuals that had an impact on these events. Meaning.

Explanation:

5 0
2 years ago
Read 2 more answers
A 2 kg ball is moving 3 m/s when it starts rolling up a hill.
AURORKA [14]

Answer:

the height reached is = 0.458 [m]

Explanation:

We need to make a sketch of the ball and see the location of the reference point where the potential energy is zero. But the kinetic energy will be defined by the following expression:

Ek=\frac{1}{2} *m*v^{2} \\where:Ek= kinetic energy [J]\\m = mass of the ball [kg]\\v = velocity of the ball [m/s]

Replacing the values on the equation we have:

Ek=\frac{1}{2}*(2)*(3^{2} )\\ Ek=9[J]\\

This kinetic energy will be transformed in potential energy in the moment when the ball starts to rolling up. Therefore the maximum height reached by the ball depends of the initial velocity given to the ball.

Ek=Ep\\where\\Ep=potential energy [J]\\Ep=m*g*h\\where\\g=gravity = 9.81[m/s^2]\\h=height reached [m]\\

Now we have:

h=\frac{Ep}{m*g} \\h=\frac{9}{2*9.81} \\\\h=0.45 [m]

In that moment when the ball reach the 0.45 [m] the potencial energy will be maximum and equal to the kinetic energy when the ball has a velocity of 3[m/s]

6 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the
Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height,  is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

3 0
2 years ago
Read 2 more answers
A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion s=ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

 Substituting

    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion v^2=u^2+2as, where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8m/s^2

    Substituting

        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion v^2=u^2+2as, where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8m/s^2

   Substituting

     0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m

  Maximum height reached = 10.65 m

8 0
3 years ago
Other questions:
  • A ball with a mass of 0.25 kg hits a gym ceiling with a force of 78.0 n. what happens next?
    15·1 answer
  • The cancellation of two waves occurs because of which of the following?
    9·1 answer
  • What is the work done by the electric force to move a 1 c charge from a to b?
    8·1 answer
  • During a race, a dragster is 200m from the finish line when something goes wrong and it stops accelerating. It travels at a cons
    14·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
    7·2 answers
  • What is momentum in physics​
    13·2 answers
  • in the absences of friction, gravity, and all other external forces, what kind of speed will an object display if it’s travel fr
    14·1 answer
  • HEY CAN ANYONE PLS ANSWER DIS!!!!!!
    6·1 answer
  • You are hiking in Yellowstone National Park. A park ranger is speaking to students visiting a hot spring. Temperatures there can
    9·1 answer
  • Describe how particles of solute behave when a solution is saturated.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!