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soldi70 [24.7K]

2 years ago

10

A gas is heated from 263 K to 298 K, and the volume is increased from 24 L to 35 L. If the original pressure is 1 atm, what woul

d the final pressure be? *

1 answer:

Sloan [31]2 years ago

4 0

Since for closed system moles of the gas is always conserved

so as per idea gas equation we can say

$n = \frac{PV}{RT}$

so here we can say

$n_1 = n_2$

so here we have

$\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}$

as we know that

$T_1 = 263 K$

$T_2 = 298 K$

$V_1 = 24 L$

$V_2 = 35 L$

$P_1 = 1 atm$

now from above equation

$\frac{1*24}{263} = \frac{P*35}{298}$

on solving above equation we have

$P = 0.78 atm$

so here pressure will be 0.78 atm

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