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soldi70 [24.7K]
3 years ago
10

A gas is heated from 263 K to 298 K, and the volume is increased from 24 L to 35 L. If the original pressure is 1 atm, what woul

d the final pressure be? *
Physics
1 answer:
Sloan [31]3 years ago
4 0

Since for closed system moles of the gas is always conserved

so as per idea gas equation we can say

n = \frac{PV}{RT}

so here we can say

n_1 = n_2

so here we have

\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}

as we know that

T_1 = 263 K

T_2 = 298 K

V_1 = 24 L

V_2 = 35 L

P_1 = 1 atm

now from above equation

\frac{1*24}{263} = \frac{P*35}{298}

on solving above equation we have

P = 0.78 atm

so here pressure will be 0.78 atm

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