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Helen [10]
3 years ago
8

Object is dropped from the top of a building that is 1125 m tall at the point when it’s speed is 30 m/s how far has it fallen

Physics
1 answer:
FrozenT [24]3 years ago
4 0

-- Gravity makes a falling object fall 9.8 m/s faster every second.

-- So, it reaches the speed of 30 m/s in (30/9.8) = 3.06 seconds after it's dropped.

-- The distance an object falls from rest is D = 1/2 (acceleration) (time)²

D = 1/2 (9.8 m/s²) (3.06 sec)²

D = (4.9 m/s²) (9.37 sec²)

<em>D = 45.8 meters</em>

Notice that we don't care how high the building is.  The problem works just as long as the object can reach 30 m/s before it hits the ground.  That  turns out to be anything higher than 45.8 meters for the drop . . . maybe something like 13 floors or more.

Now I'll go a little farther for you !  Writing the last paragraph made me a little curious and uncomfortable.  So I went and looked up the world's tallest buildings . . . and I found out that this problem could never happen !

The tallest building in the world now is the Burj Khalifa, in  Dubai.  It has 163 floors, and it's 828 meters high !  That's 2,717 feet.  It's gonna be a long time before there's a building that's 1125 meters tall, like this problem says.  That's close to 3700 feet . . . I've had flying lessons where I wasn't that far off the ground !

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A baseball is hit nearly straight up into the air with a speed of 22 m/s. (a) how high does it go? (b) how long is it in the air
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Refer to the diagram shown below.

When the ball attains maximum height, it will have zero vertical velocity.
The maximum height, h. obeys the equation
0 = (22 m/s)² - 2*(9.8 m/s²)*(h m)
h = 22²/(2*9.8) = 24.694 m

Answer: The maximum height attained is 24.7 m (nearest tenth)

Part b.
The vertical height traveled by the ball obeys the equation
h = (22 m/s)t - (1/2)*(9.8 m/s²)*(t s)²
where
h = vertical height, m
g = 9.8 m/s², acceleration due to gravity
t = time, s

To find how long the ball stays in the air, set h = 0 to obtain
4.9t² - 22t = 0
t(4.9t - 22) = 0
t = 0, or t = 22/4.9 = 4.49 s
t = 0 corresponds to the launch, and t = 4.49 s corresponds to when the ball retuns to the ground.

Answer: The ball stays in the air for 4.5 s (nearest tenth)

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3 years ago
How are some types of collisions different from others?
lyudmila [28]
There are two general types of collisions, inelastic and elastic. 
Inelastic collisions occur when two objects collide but neither of them bounce away from each other.
Collisions in which the objects do not touch each other are elastic. (Ex: Rutherford Scattering) 
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Of the following approximate conversions of celsius into fahrenheit, which is most accurate? a. 24°c almost-equals 75.9°f b. 2°c
Softa [21]

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

<h3>What is Scale of Temperature?</h3>

Scale of temperature is simply a method used in calibrating the physical quantity of temperature in metrology.

Conversion of Celsius into Fahrenheit, Formula is expressed as;

Degree = (0 × 9/5) + 32 = Fahrenheit

First we check each option;

A) 24°c almost-equals 75.9°f

24°C = (24 × 9/5) + 32 = 75.2°F

B) 2°C almost-equals 35.8°f

2°C = (2 × 9/5) + 32 = 35.6°F

C) 34°C almost-equals 92.7°f

34°C = (34 × 9/5) + 32 = 93.2°F

D) 13°c almost-equals 55.0°f

13°C = (13 × 9/5) + 32 = 55.4°F

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

Learn more about temperature scales here: brainly.com/question/88395

#SPJ4

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1 year ago
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